Answer:
i would but there is nothing to awnser soooo!!! sorry
Explanation:
Answer:
1.21 g of Tris
Explanation:
Our solution if made of a solute named Tris
Molecular weight of Tris is 121 g/mol
[Tris] = 100 mM
This is the concentration of solution:
(100 mmoles of Tris in 1 mL of solution) . 1000
Notice that mM = M . 1000 We convert from mM to M
100 mM . 1 M / 1000 mM = 0.1 M
M = molarity (moles of solute in 1 L of solution, or mmoles of solute in 1 mL of solution). Let's determine the mmoles of Tris
0.1 M = mmoles of Tris / 100 mL
mmoles of Tris = 100 mL . 0.1 M → 10 mmoles
We convert mmoles to moles → 10 mmol . 1mol / 1000mmoles = 0.010 mol
And now we determine the mass of solute, by molecular weight
0.010 mol . 121 g /mol = 1.21 g
It’s probably Mercury I’m not sure
Answer:
43.2 mol C
115 mol H
158 mol of atoms
Explanation:
Step 1: Given data
Moles of C₃H₈: 14.4 mol
Step 2: Calculate the number of moles of C
The molar ratio of C₃H₈ to C is 1:3. The moles of C are 3/1 × 14.4 mol = 43.2 mol.
Step 3: Calculate the number of moles of H
The molar ratio of C₃H₈ to H is 1:(. The moles of H are 8/1 × 14.4 mol = 115 mol.
Step 4: Calculate the total number of moles of atoms
n = nC + nH = 43.2 mol + 115 mol = 158 mol
