Answer:
The molarity of urea in this solution is 6.39 M.
Explanation:
Molarity (M) is <em>the number of moles of solute in 1 L of solution</em>; that is

To calculate the molality, we need to know the number of moles of urea and the volume of solution in liters. We assume 100 grams of solution.
Our first step is to calculate the moles of urea in 100 grams of the solution,
using the molar mass a conversion factor. The total moles of 100g of a 37.2 percent by mass solution is
60.06 g/mol ÷ 37.2 g = 0.619 mol
Now we need to calculate the volume of 100 grams of solution, and we use density as a conversion factor.
1.032 g/mL ÷ 100 g = 96.9 mL
This solution contains 0.619 moles of urea in 96.9 mL of solution. To express it in molarity, we need to calculate the moles present in 1000 mL (1 L) of the solution.
0.619 mol/96.9 mL × 1000 mL= 6.39 M
Therefore, the molarity of the solution is 6.39 M.
#1
Moles of Oxygen =3
Molecules:-
- 3×Avagadro no
- 3(6.022×10²³)
- 18.066×10²³
- 1.8066×10²²molecules
#2
Its because according to law of conservation of mass- Mass is neither created nor destroyed
AS ITS BALANCED SO BOTH SIDES ARE SAME .
HENCE THEY OBEY
The molar mass of the unknown gas is 184.96 g/mol
<h3>Graham's law of diffusion </h3>
This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e
R ∝ 1/ √M
R₁/R₂ = √(M₂/M₁)
<h3>How to determine the molar mass of the unknown gas </h3>
The following data were obtained from the question:
- Rate of unknown gas (R₁) = R
- Rate of CH₄ (R₂) = 3.4R
- Molar mass of CH₄ (M₂) = 16 g/mol
- Molar mass of unknown gas (M₁) =?
The molar mass of the unknown gas can be obtained as follow:
R₁/R₂ = √(M₂/M₁)
R / 3.4R = √(16 / M₁)
1 / 3.4 = √(16 / M₁)
Square both side
(1 / 3.4)² = 16 / M₁
Cross multiply
(1 / 3.4)² × M₁ = 16
Divide both side by (1 / 3.4)²
M₁ = 16 / (1 / 3.4)²
M₁ = 184.96 g/mol
Learn more about Graham's law of diffusion:
brainly.com/question/14004529
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Answer:
CH4 + 2 O2 - - - > CO2 + 2 H2O
Explanation:
hope this helps,
you can check by adding all the numbers on both sides
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