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Over [174]
2 years ago
14

Why does nitrogen have stronger attractive forces between its nucleus and valence electrons than phosphorus?

Chemistry
1 answer:
timofeeve [1]2 years ago
3 0

Answer:

Nitrogen atom is small in size than phosphorus thus the bond between its nucleus and valence electrons are stronger than phosphorus.

Hope it helps...。◕‿◕。

You might be interested in
ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J.
timofeeve [1]

Complete question:

ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J. calculate the magnitude of q for the process.

Answer:

The magnitude of q for the process 568 J.

Explanation:

Given;

change in internal energy of the gas, ΔU = 475 J

work done by the gas, w = 93 J

heat added to the system, = q

During gas expansion process, heat is added to the gas.

Apply the first law of thermodynamic to determine the magnitude of heat added to the gas.

ΔU = q - w

q = ΔU +  w

q = 475 J  +  93 J

q = 568 J

Therefore, the magnitude of q for the process 568 J.

6 0
3 years ago
Part APart complete A sample of sodium reacts completely with 0.568 kg of chlorine, forming 936 g of sodium chloride. What mass
yan [13]

Answer: 368 grams of sodium reacted.

Explanation:

The balanced reaction is :

2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)

\text{Moles of chlorine}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of chlorine}=\frac{0.568\times 1000g}{71g/mol}=8moles

\text{Moles of sodium chloride}=\frac{936g}{58.5g/mol}=16mol    

According to stoichiometry :

2 moles of NaCl are formed from = 2 moles of Na

Thus 16 moles of NaCl are formed from=\frac{2}{2}\times 16=16moles  of Na

Mass of Na=moles\times {\text {Molar mass}}=16moles\times 23g/mol=368g

Thus 368 grams of sodium reacted.

4 0
3 years ago
21. Draw Lewis structure
Veseljchak [2.6K]

Answer:

C contains one N and three I atoms

7 0
2 years ago
Gaseous methane (CH4) will react with gaseous oxygen (O2) to produce gaseous carbon dioxide (CO) and gaseous water (H2O) . Suppo
Leto [7]

Answer:

0 g.

Explanation:

Hello,

In this case, since the reaction between methane and oxygen is:

CH_4+2O_2\rightarrow CO_2+2H_2O

If 0.963 g of methane react with 7.5 g of oxygen the first step is to identify the limiting reactant for which we compute the available moles of methane and the moles of methane consumed by the 7.5 g of oxygen:

n_{CH_4}=0.963gCH_4*\frac{1molCH_4}{16gCH_4}=0.0602molCH_4\\ \\n_{CH_4}^{consumed}=7.5gO_2*\frac{1molO_2}{32gO_2}*\frac{1molCH_4}{2molO_2} =0.117molCH_4

Thus, since oxygen theoretically consumes more methane than the available, we conclude the methane is the limiting reactant, for which it will be completely consumed, therefore, no remaining methane will be left over.

left\ over=0g

Regards.

7 0
2 years ago
What causes the Moon to be illuminated?
alexgriva [62]

Answer:

reflection

Explanation:

the moon reflects sunlight causing it to look brighter. the sun is not a medium as light doesn't require a. medium to travel. nor is a moon concave...

hope it helps

8 0
1 year ago
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