If m ACD = 30 => m DCB = 60.
In triangle ACD:
AC^{2}+CB^{2}=AB^{2} => AB=
=32.
=> P=16+32+
=48 +.
In triangle ACD:
AC^{2}+CB^{2}=AB^{2} => AB=
=> P=16+32+
(4x + 8) + (7x + 3) please help
2 answers:
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The slope m of a line
through points 
and 
is given by :<span>
Thus, the slope of the line passing through points </span><span>(−1, 7) and (2, 10) is
</span>
<span>
The equation of a line with slope m passing through a point P(a, b) is given by
(y-b)=m(x-a).
We can consider any of the points (-1, 7), or (2, 10). Let's choose (2, 10):
y-10=1(x-2)
y-10=x-2
y-x=-2+10
y-x=8
Answer: </span><span>C. −x+y=8</span>
Thus, the slope of the line passing through points </span><span>(−1, 7) and (2, 10) is
</span>
<span>
The equation of a line with slope m passing through a point P(a, b) is given by
(y-b)=m(x-a).
We can consider any of the points (-1, 7), or (2, 10). Let's choose (2, 10):
y-10=1(x-2)
y-10=x-2
y-x=-2+10
y-x=8
Answer: </span><span>C. −x+y=8</span>