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xxTIMURxx [149]
3 years ago
11

A car starts from the origin and is driven 1.88 km south, then 9.05 km in a direction 47° north of east. Relative to the origin,

what is the car's final location? a) Express your answer in terms of an angle (in degree)
b) and a distance.
Physics
1 answer:
WINSTONCH [101]3 years ago
4 0

Answer:

(a) θ = 55.85 degree

(b) 7.89 km

Explanation:

Using vector notations

A = 1.88 km south = 1.88 (- j) km = - 1.88 j km

B = 9.05 km 47 degree north of east

B = 9.05 ( Cos 47 i + Sin 47 j) km

B = (6.17 i + 6.62 j) km

Net displacement is

D = A + B

D = - 1.88 i + 6.17 i + 6.62 j = 4.29 i + 6.62 j

(a) Angle made with positive X axis

tanθ = 6.62 / 4.29 = 1.474

θ = 55.85 degree

(b) distance = Distance = \sqrt{(4.29)^{2} + (6.62)^{2}}

distance = 7.89 km

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Answer:

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Power consumed = IV

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If a blow-dryer and a vacuum cleaner each operate with a voltage of 120 V and the current rating of the blow-dryer is 12 A, while that of the vacuum cleaner is 4.7 A then their individual power rating is calculated thus;

a) For blow-dryer

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b) For vacuum cleaner:

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Energy used by blow dryer = 1440×20×60

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Energy used up by vacuum cleaner = 564×46×60

= 564×2760

= 1,556,640Joules

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