Answer:
5,000J
Explanation:
Work = Force x Distance
Distance back and forth is canceled out, so either the answer is + or -
5.0m + 5.0m = 10.0m
500N x 10.0m = 5,000J
Answer with Explanation:
We are given that
Diameter of fighter plane=2.3 m
Radius=
a.We have to find the angular velocity in radians per second if it spins=1200 rev/min
Frequency=
1 minute=60 seconds
Angular velocity=
Angular velocity=
b.We have to find the linear speed of its tip at this angular velocity if the plane is stationary on the tarmac.

c.Centripetal acceleration=
Centripetal acceleration==
Answer:
The angle between the magnetic field and the wire’s velocity is 19.08 degrees.
Explanation:
Given that,
Potential difference, V = 53 mV
Length of the wire, l = 12 cm = 0.12 m
Magnetic field, B = 0.27 T
Speed of the wire, v = 5 m/s
Due to its motion, an emf is induced in the wire. It is given by :

Here,
is the angle between magnetic field and the wire’s velocity

So, the angle between the magnetic field and the wire’s velocity is 19.08 degrees.
Answer:
8.89288275 m/s
Explanation:
F = Tension = 54 N
= Linear density of string = 5.2 g/m
A = Amplitude = 2.5 cm
Wave velocity is given by

Frequency is given by

Angular frequency is given by

Maximum velocity of a particle is given by

The maximum velocity of a particle on the string is 8.89288275 m/s
Positively charged protons in the nucleus of the gold atom .... rutherford scattering ???