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bogdanovich [222]
3 years ago
8

Is gravity considered a constant or field force?explain

Physics
1 answer:
-Dominant- [34]3 years ago
7 0
Gravity Is Considered Field Force Since The Earth Does Not Have To Actually “Touch” An Object To Pull It Toward The Earth !
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A forklift pushes a box with a force of 500 N across the floor for a distance of 5.0 m, then turns around and pushes with the sa
yanalaym [24]

Answer:

5,000J

Explanation:

Work = Force x Distance

Distance back and forth is canceled out, so either the answer is + or -

5.0m + 5.0m = 10.0m

500N x 10.0m = 5,000J

4 0
2 years ago
The propeller of a World War II fighter plane is 2.30 m in diameter. (a) What is its angular velocity in radians per second if i
Sergio [31]

Answer with Explanation:

We are given that

Diameter of fighter plane=2.3 m

Radius=r=\frac{d}{2}=\frac{2.3}{2}=1.15 m

a.We have to find the angular velocity in radians per second if it spins=1200 rev/min

Frequency=\frac{1200}{60}=20 Hz

1 minute=60 seconds

Angular velocity=\omega=2\pi f

Angular velocity=2\times \frac{22}{7}\times 20=125.7 rad/s

b.We have to find the linear speed of its tip at this  angular velocity if the plane is stationary on the tarmac.

v=r\omega=1.15\times 125.7=144.56 m/s

c.Centripetal acceleration=\omega^2 r=(125.7)^2(1.15)=18170.56 m/s^2

Centripetal acceleration==\frac{18170.56\times g}{9.81}=1852.25 g m/s^2

7 0
3 years ago
A potential difference of 53 mV is developed across the ends of a 12.0-cm-longwire as it moves through a 0.27 T uniform magnetic
Klio2033 [76]

Answer:

The angle between the magnetic field and the wire’s velocity is 19.08 degrees.                                            

Explanation:

Given that,

Potential difference, V = 53 mV

Length of the wire, l = 12 cm = 0.12 m

Magnetic field, B = 0.27 T

Speed of the wire, v = 5 m/s

Due to its motion, an emf is induced in the wire. It is given by :

\epsilon=Blv\sin\theta

Here,

\theta is the angle between magnetic field and the wire’s velocity

\sin\theta=\dfrac{\epsilon}{Blv}\\\\\sin\theta=\dfrac{53\times 10^{-3}}{0.27\times 0.12\times 5}\\\\\sin\theta=0.327\\\\\theta=19.08^{\circ}

So, the angle between the magnetic field and the wire’s velocity is 19.08 degrees.

8 0
3 years ago
A string that is under 54.0 N of tension has linear density 5.20 g/m . A sinusoidal wave with amplitude 2.50 cm and wavelength 1
kicyunya [14]

Answer:

8.89288275 m/s

Explanation:

F = Tension = 54 N

\mu = Linear density of string = 5.2 g/m

A = Amplitude = 2.5 cm

Wave velocity is given by

v=\sqrt{\frac{F}{\mu}}\\\Rightarrow v=\sqrt{\frac{54}{5.2\times 10^{-3}}}\\\Rightarrow v=101.90493\ m/s

Frequency is given by

f=\frac{v}{\lambda}\\\Rightarrow f=\frac{101.90493}{1.8}\\\Rightarrow f=56.61385\ Hz

Angular frequency is given by

\omega=2\pi f\\\Rightarrow \omega=2\pi 56.61385\\\Rightarrow \omega=355.71531\ rad/s

Maximum velocity of a particle is given by

v_m=A\omega\\\Rightarrow v_m=0.025\times 355.71531\\\Rightarrow v_m=8.89288275\ m/s

The maximum velocity of a particle on the string is 8.89288275 m/s

5 0
2 years ago
When positively charged particles were radiated onto a gold atom, a few of the particles bounced back. Which of the following ca
ratelena [41]

Positively charged protons in the nucleus of the gold atom .... rutherford scattering ???


3 0
3 years ago
Read 2 more answers
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