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4 years ago

Could a nucleus that has one proton but no neutrons exist?

1 answer:

8 0

Yes, but there is only 1 atom like that and is is hydrogen. Hydrogen is the only element that could have a nucleus with one proton and no neutrons exist.

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Coriolis effect that's due to the motion of the Earth

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3 years ago

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3 years ago

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2 years ago

An infinite sheet carries a uniform, positive charge per unit area. The electric field produced by the sheet is represented by p

nexus9112 [7]

Complete Question

An infinite sheet carries a uniform, positive charge per unit area. The electric field produced by the sheet is represented by parallel lines drawn with a density N lines per m2 that are perpendicular to and away from the sheet. The charge per unit area on the sheet is doubled. How should the density of the electric field lines be changed?

A It should stay the same

B It should be quadrupled.

C It should be quintupled

D It should be doubled.

E It should be tripled

Answer:

Option D is the correct option

Explanation:

Generally electric field is mathematically represented as

$E = \frac{\sigma}{\epsilon_o}$

Where $\sigma$ is the charge per unit area (Charge density )

From the question we are told that $\sigma$ is doubled hence the

$E = \frac{2 \sigma }{\epsilon_o}$

Looking the equation above we see that the value of the electric field will also double given that it is directly proportional to the charge density

8 0

3 years ago

A circuit consists of a 6 ohm resistor, a 0.2 farad capacitor, and an AC voltage source supplying V(t) = 120 cos(20 t) volts. Wr

Zinaida [17]

Answer:

q = 24 cos (20t) (1- e (-t / 1.2))

Explanation:

To work this circuit we use the mesh equation (Kirchoff) that states that the voltage in a closed circuit is zero

Vg + Vr + Vc = 0

Where Vg is the generator voltage, Vr the resistance voltage and Vc the capacitor voltage

Vg = 120 cos 20t = V

Vr = i R

Vc = q / C

We see that in one term we have the current (i) and in another the load (q), but there is a relationship between the two

i = dq / dt

Let's replace in the initial equation

V + R dq / dt + q / C = 0

Reorder the terms

Rdq / dt + q / C - V = 0

dq / dt + q / rC - V / R = 0

dq / dt = V / r -q / RC

dq / (V / R -q / RC) = dt

we integrate

∫I dq / (V / R - 1 / RC q) = ∫ dt

We change variables

u = (V / R - 1 / RC q)

du = -1 / RC dq

∫ dq / (V / R - 1 / RC q) = -RC ∫ du / u

-RC ln u = -RC ln (V / R - 1 / RC q)

We evaluate between the limits of integration, the lower t = 0 q (0) = 0

-RC [ln (V / R - 1 / RC q) - ln (V / R)] = t

[ln (V / R - 1 / RC q) - ln (V / R)] = -t / RC

Ln (V / R - 1 / RC q) / (V / R)] = -t / RC

Ln (1 - 1 / VC q)) = (-t / RC)

Ln (VC- q) = ln (VC) (-t / RC)

VC-q = VC e (-t / RC)

q = VC - Vc e (-t / RC)

q = VC (1- e (-t / RC)

We substitute the values they give us

q = (120 cos (20t) 0.2) (1- e (-t / 6 0.2))

q = 24 cos (20t) (1- e (-t / 1.2))

7 0

4 years ago