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Damm [24]
3 years ago
14

A laser pulse takes 2.56 seconds to travel from Earth to the Moon and return. Use this to calculate how far away the Moon is. Ho

w might this time delay affect conversations between an astronaut on the Moon and someone back on Earth
Physics
1 answer:
Deffense [45]3 years ago
7 0

Answer:

x = 3.84\times 10^{5}\,km

This delay affect conversations in the sense that recipient will be receive the message just 2.56 seconds after the message was sent.

Explanation:

The laser pulse has an ondulatory nature as electromagnetic wave, which can travel in the void. Speed of light is constant and distance between Earth and the Moon is:

x = 0.5\cdot c\cdot \Delta t

x = 0.5\cdot (3\times 10^{5}\,\frac{km}{s})\cdot (2.56\,s)

x = 3.84\times 10^{5}\,km

This delay affect conversations in the sense that recipient will be receive the message just 2.56 seconds after the message was sent.

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If a baseball's velocity is increased to four times its original velocity, by what factor does its kinetic energy increase
jeyben [28]

Answer:

16 times

Explanation:

Original

KE(i)  = 1/2mv²

After increasing

KE(f) = 1/2m(4v)²

KE(f) = 8mv²

KE(f)/KE(i) = 8 x 2 = 16

8 0
3 years ago
2-The amount of internal energy needed to raise the temperature of 0.25kg of water by 0.2°C is 209.3 J. How fast must a 0.25 kg
Yakvenalex [24]

Answer:

40.92 m/s

Explanation:

The computation is shown below:

Ek = 1 ÷2mv²...............................(1)

v = √(2Ek/m).......................... (2)

Here EK denotes kinetic energy

m denotes mass

v denotes velocity

Given that

m = 0.25kg and Ek = 209.3J

So,

v = √(2×209.3 ÷0.25)

= √1674.4

= 40.92 m/s

7 0
3 years ago
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bagirrra123 [75]
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\lambda= \frac{c}{f}
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\lambda= \frac{3\cdot 10^8 m/s }{7.20 \cdot 10^{21} Hz}=4.17 \cdot 10^{-14} m
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ikadub [295]
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8 0
3 years ago
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Leno4ka [110]
The answer is donate, therefore elements with positive valences usually donate electrons
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3 years ago
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