16.7 m/s
<em>To</em><em> </em><em>deter</em><em>mine</em><em> </em><em>the </em><em>speed</em><em> </em><em>we</em><em> </em><em>use</em><em> </em><em>the</em><em> </em><em>formula</em><em>:</em><em> </em><em>Dista</em><em>nce</em><em> </em><em>÷</em><em> </em><em>Time</em><em> </em><em>so</em><em>,</em><em> </em><em>5</em><em>0</em><em> </em><em>÷</em><em> </em><em>3</em><em> </em><em>=</em><em> </em><em>1</em><em>6</em><em>.</em><em>6</em><em>6</em><em>.</em><em>.</em><em>.</em><em> </em><em>(</em><em> </em><em>rounde</em><em>d</em><em> </em><em>off</em><em> </em><em>to</em><em> </em><em>1</em><em>.</em><em>d</em><em>.</em><em>p</em><em> </em><em>is</em><em> </em><em>1</em><em>6</em><em>.</em><em>7</em><em>)</em><em>.</em>
Answer: A. The total displacement divided by the time and C. The slope of the ant's displacement vs. time graph.
Explanation:
Hi! The question seems incomplete, but I found the options on the internt:
A. The total displacement divided by the time.
B. The slope of the ant's acceleration vs. time graph.
C. The slope of the ant's displacement vs. time graph.
D. The average acceleration divided by the time.
Now, since we know the ant is travelling at a constant speed, its average velocity 
will be expressed by the following equation:
Where:
is the ant's total displacement
is the time it took to the ant to travel to the kitchen
Hence one of the correct options is: A. The total displacement divided by the time
On the other hand, this can be expressed by a displacement vs. time graph graph, where the slope of that line leads to the equation written above. So, the other correct option is:
C. The slope of the ant's displacement vs. time graph.
The answer is C. because the lines will look the same as the earths gravity field (you can look up a graph)
Explanation:
Spaceship A moves at 0.800 in the positive – direction, while spaceship B moves in the opposite direction at 0.750 (both speeds are measured relative to Earth). What is the velocity {A,B} of spaceship A relative to spaceship B
It all depends on the SIZE of the balloon.
If the balloon is made of really tough rubber, and it holds the helium in the same volume as the solid iron block, then the buoyant force of the atmosphere is the same for both objects.
But if the balloon is just some flimsy stuff, and it lets the helium expand to a much bigger volume than the iron block, then the buoyant force on the balloon is greater than the buoyant force on the solid iron block.
In fact, it DOESN'T MATTER what's in the balloon and what's in the block. It doesn't matter whether either one of them is solid, liquid, or gas, and it doesn't matter whether they have the same or different mass.
Whichever one has greater VOLUME has a greater buoyant force of atmosphere acting on it.
