Find the shape of the area below. Please thank you

How can I find an outlier in a box and whisker plot?

Temka [501]

Answer:

Generally it's one that is just out of the way, the extreme outcast.

4 0

3 years ago

Rosita earns money by walking dogs after school and on weekends.She walks Madeline every other day,buddy every fourth day,and er

leonid [27]

On 12th day Rosita will walk all three dogs

Solution:

Given that Rosita earns money by walking dogs after school and on weekends

She walks Madeline every other day,buddy every fourth day,and ernie every third day

Today she walked all three dogs

To find: the day when she walked all three dogs

From given question,

Madeline is walked every other day means every two days: 2

Buddy is walked every fourth day: 4

Ernie is walked every third day: 3

To find the day when she walked all three dogs, we have to find the least common multiple (LCM) of 2, 4, 3

L.C.M of 2, 4, 3:

List all prime factors for each number

Prime Factorization of 2 shows:

2 is prime => $2^1$

Prime Factorization of 3 shows:

3 is prime => $3^1$

Prime Factorization of 4 is:

$2 \times 2 = 2^2$

For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.

The new superset list is

2, 2, 3

Multiply these factors together to find the LCM.

LCM = 2 x 2 x 3 = 12

Thus on 12th day Rosita will walk all three dogs

4 0

4 years ago

Determine the distance between -7 and 7

PtichkaEL [24]

Answer= 14

Distance between-7 and 0 is 7 plus the distance between 7and 0 which is also 7 Gives is the total distance of 14

3 0

3 years ago

Calculate the following limit:

aleksklad [387]

$\lim_{x\to\infty}\dfrac{\sqrt x}{\sqrt{x+\sqrt{x+\sqrt x}}}=\\
\lim_{x\to\infty}\dfrac{\dfrac{\sqrt x}{\sqrt x}}{\dfrac{\sqrt{x+\sqrt{x+\sqrt x}}}{\sqrt x}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{\dfrac{x+\sqrt{x+\sqrt x}}{x}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{x}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{\sqrt{x^2}}}}=\\$
$\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{x+\sqrt x}{x^2}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\dfrac{\sqrt x}{\sqrt{x^4}}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{x}{x^4}}}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{1}{x^3}}}}}=\\
=\dfrac{1}{\sqrt{1+\sqrt{0+\sqrt{0}}}}=\\$
$=\dfrac{1}{\sqrt{1+0}}=\\
=\dfrac{1}{\sqrt{1}}=\\
=\dfrac{1}{1}=\\
1
$

8 0

3 years ago

Two pillars have been delivered for the support of a shade structure in the backyard. they are both ten feet tall and the cross

BartSMP [9]

The steps to determine whether the pillars have the same volume are;

First, we must know that the volume of an object of uniform surface area is the product of its Area and height.

The uniform area of each pillar is then evaluated and if equal;

Both pillars can be concluded to have the same volume.

We must first recall that for various shapes, the volume of the shape is a function of its height.

For example: a A cylinderical pillar and a rectangular prism pillar;

Volume of a cylinder = πr²h

Volume of a Cuboid = l × w × h

Since h = h.

Therefore, for both pillars to have the same volume; their Areas must be equal.

πr² = l × w

Learn more about Area and volume here

brainly.com/question/987829

#SPJ4

3 0

2 years ago