It's the first answer choice.
Steps:
-3x^2y^2x^4
(Apply the exponent rule)
x^4x^2 = x^2+4 = x^6
= -3x^6y^2
Answer:
The length of the interval during which no messages arrive is 90 seconds long.
Step-by-step explanation:
Let <em>X</em> = number of messages arriving on a computer server in an hour.
The mean rate of the arrival of messages is, <em>λ</em> = 11/ hour.
The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 11.
The probability mass function of <em>X</em> is:

It is provided that in <em>t</em> hours the probability of receiving 0 messages is,
P (X = 0) = 0.76
Compute the value of <em>t</em> as follows:

Thus, the length of the interval during which no messages arrive is 90 seconds long.
Answer:
g (-2) = 22
Step-by-step explanation:
Evaluate g( -2) if g(x) = x^2 – 4x + 10
g(-2) = (-2)^2 - 4(-2) + 10
g(-2) = 4 + 8 + 10
g (-2) = 22
Answer:
Thursday=80%
Saturday=82 %
Step-by-step explanation:
Thursday trains not late=40-8=32
% trains not late=32/40×100=80
Saturday trains not late=50-9=41
% trains not late on Saturday=41/50×100=82