I believe the answer is the third one.
Circumpolar constellations stay in the sky. Because of the rotation of the Earth and its orbit around the Sun, we divide the stars and constellations into two groups. Some stars & constellations never rise nor set, and they are called circumpolar.
An isotope is a variant on an element that has a different atomic weight from other variants
Answer:
The correct option is: (A) Ketones cannot be oxidized further
Explanation:
Oxidation refers to the gain of oxygen or the formation of carbon-oxygen bond (C-O bond).
Alcohols are organic compounds containing at least one hydroxyl group. These compounds can be further classified into <em>primary (R-CH₂-OH), secondary (R¹R²CH-OH) and tertiary alcohols (R¹R²R³C-OH).</em>
- The <u>partial oxidation of </u><u>primary alcohol</u><u> gives </u><u>aldehyde</u> (R-CHO). Further <u>oxidation of aldehyds gives </u><u>carboxylic acid </u>(R-COOH). <u>Primary alcohol can also be oxidized directly to carboxylic acid.</u> <em>However, the carboxylic acid can not be further oxidized.</em>
![R-CH_{2}-OH \overset{[O]}{\rightarrow} R-CHO \overset{[O]}{\rightarrow} R-COOH \\R-CH_{2}-OH \overset{[O]}{\rightarrow} R-COOH](https://tex.z-dn.net/?f=R-CH_%7B2%7D-OH%20%5Coverset%7B%5BO%5D%7D%7B%5Crightarrow%7D%20R-CHO%20%5Coverset%7B%5BO%5D%7D%7B%5Crightarrow%7D%20R-COOH%20%5C%5CR-CH_%7B2%7D-OH%20%5Coverset%7B%5BO%5D%7D%7B%5Crightarrow%7D%20R-COOH)
- <u>Oxidation of </u><u>secondary alcohols</u><u> gives </u><u>ketones</u> (R¹R²C=O), <em>which can not be oxidized further.</em>
![R^{1}R^{2}CH-OH \overset{[O]}{\rightarrow} R^{1}R^{2}C=O](https://tex.z-dn.net/?f=R%5E%7B1%7DR%5E%7B2%7DCH-OH%20%5Coverset%7B%5BO%5D%7D%7B%5Crightarrow%7D%20R%5E%7B1%7DR%5E%7B2%7DC%3DO)
- Whereas, tertiary alcohols are resistant to oxidation.
<u>Therefore, the correct statement regarding oxidation is </u><u>(A)</u><u> </u><em><u>Ketones cannot be oxidized further</u></em><u>.</u>
Answer: I am sorry I don't know but my mom say's it doesn't.
Explanation: no explanation