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Amiraneli [1.4K]
3 years ago
8

35 POINTS!

Chemistry
2 answers:
Kobotan [32]3 years ago
3 0

Answer:

A: A boulder that is falling after being pushed off a cliff.

C: A pebble in a slingshot before it has been shot.

Explanation:

These are examples of potential energy because they are holding energy before it is released.

Hope this helps

Ann [662]3 years ago
3 0

Answer:

Your two answers would be 'An iron nail as it moves towards a magnet' and 'A pebble in a slingshot before it has been shot'.

Explanation:

Potential energy is energy stored for when the kinetic energy needs to be released. Kinetic energy is released when objects are in full motion.

Options A and D (The boulder one and the pebble traveling as it is shot) imply that the objects are moving and already using kinetic energy. Therefore, the other two options B and D, stated in the answer box, make the most sense.

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<span>Helium = 1
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If we take nitrogen-15 for example; The number 15 tells you that the isotope has a mass of 15. Now if you look on the periodic table, Nitrogen has a proton number of 7. Only protons and neutrons have a mass, electrons are considered to be negligable. Therefore the number of neutrons Nitrogen-15 contains is 15 - 7 = 8 </span>
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9.25

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number of moles of NaOH = 0.80  mol/L × 50 ×  10⁻³L

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The equation for the reaction is expressed as:

NH^+_{4(aq)} \ + OH^-_{(aq)} ------> NH_{3(g)} \ + H_2O_{(l)}

The ICE Table is shown below as follows:

                            NH^+_{4(aq)} \ + OH^-_{(aq)} ------> NH_{3(g)} \ + H_2O_{(l)}

Initial (M)              0.08            0.04                            0

Change (M)         - 0.04          -0.04                          + 0.04

Equilibrium (M)      0.04             0                                0.04

K_a*K_b = 10^{-14} \ at \ 25^0C

K_a = \frac{10^{-14}}{K_b}

K_a = \frac{10^{-14}}{1.76*10^{-5}}

K_a= 5.68*10^{10}

pK_a = - log \ (K_a)

pK_a = - log \ (5.68*10^{-10})

pK_a = 9.25

pH = pKa + \ log (\frac{HB}{HA} )   for buffer solutions

pH = pKa + \ log (\frac{moles \ of \ base }{ moles\ of \ acid} ) since they are in the same solution

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