Question

The average kinetic energy of water at 25oC is

Answer 1

Answer: The average kinetic energy of water at $25^{o}C$ is $1.233 \times 10^{-26} J$.

Explanation:

Given: Temperature = $25^{o}C = (25 + 273) K = 298 K$

Kinetic energy is the energy acquired by the molecules of a substance due to its motion.

Formula to calculate average kinetic energy is as follows.

$K.E = \frac{3}{2}kT$

where,

T = temperature

k = Boltzmann constant = $1.38 \times 10^{-23} J/K$

Substitute the value into above formula as follows.

$K.E = \frac{3}{2}kT\\= \frac{3}{2} \times 1.38 \times 10^{-23} J/K \times 298 K \\= 1.233 \times 10^{-26} J$

Thus, we can conclude that the average kinetic energy of water at $25^{o}C$ is $1.233 \times 10^{-26} J$.