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Travka [436]
3 years ago
10

Which clouds are often associated with thunder and lightning?

Chemistry
2 answers:
FrozenT [24]3 years ago
6 0
Cumulonimbus clouds, of course!. These clouds are known to carry rain, hail, and thunder. Bigger versions are known as supercells, deadly storms that can spew out tons of rain, hail, wind, and even tornadoes!
Grace [21]3 years ago
3 0
The <span>Cumulonimbus cloud is usually associated with thunder and lightning. They are formed by water vapor and are very dense. (often seen during a thunderstorm)</span>
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S
N76 [4]

Answer:

B

Explanation:

B

4 0
3 years ago
Write a Scientific question for how temperature change affects gas inside a container
natima [27]
By scientific question, it really just means create a normal question. The example would be:
How will gas be affected if the temperature in an enclosed container is to be changed?

There are mannnyyy ways how to write a question for this, you just have to make sure you write what you are changing and how you are changing it, oh and make it sound smart haha.
7 0
3 years ago
A gas has a volume of 240 mL and a pressure of 0.99 atm. If the pressure is decreased to 0.951 atm, what is the new volume of th
irakobra [83]

V2 = 250 ml

Explanation:

Given:

P1 = 0.99 atm. V1 = 240 ml

P2 = 0.951 atm. V2 = ?

We can use Boyle's law to solve for V2

P1V1 = P2V2

V2 = (P1/P2)V1

= (0.99 atm/0.951 atm)(240 ml)

= 250. ml

6 0
3 years ago
The molecular formula for butane is C4H10. Determine the percent composition for
masya89 [10]

%Mass

Ar C = 12 g/mol, Mr C₄H₁₀ = 58 g/mol, Ar H = 1 g/mol

\tt C=\dfrac{4.12}{58}\times 100\%=82.8\%\\\\H=100\%-82.8\%=17.2\%

or

\tt H=\dfrac{10.1}{58}\times 100\%= 17.2\%

4 0
3 years ago
The reaction for photosynthesis producing glucose sugar and oxygen gas is:
uranmaximum [27]

Answer:

a. 1.12 L

Explanation:

Step 1: Write the balanced equation for the photosynthesis

6 CO₂(g) + 6 H₂O(l) ⇒ C₆H₁₂O₆(s) + 6 O₂(g)

Step 2: Calculate the moles corresponding to 2.20 g of CO₂

The molar mass of CO₂ is 44.01 g/mol.

2.20 g × 1 mol/44.01 g = 0.0500 mol

Step 3: Calculate the moles of O₂ produced

The molar ratio of CO₂ to O₂ is 6:6. The moles of O₂ produced are 6/6 × 0.0500 mol = 0.0500 mol

Step 4: Calculate the volume occupied by 0.0500 moles of O₂ at STP

At STP, 1 mole of O₂ occupies 22.4 L.

0.0500 mol × 22.4 L/1 mol = 1.12 L

4 0
3 years ago
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