Question

Calculate the value of [CH3OH][CO][H2]2 when all concentrations are 2.4. Keep in mind that the reaction may not be at equilibrium under these conditions.

Answer 1

Explanation:

The given reaction will be as follows.

            $CO + 2H_{2} \leftrightharpoons CH_{3}OH$

So, equilibrium constant for this equation will be as follows.

              $K_{c} = \frac{[CH_{3}OH]}{[CO][H_{2}]^{2}}$

As it is given that concentration of all the species is 2.4. Therefore, calculate the value of equilibrium constant as follows.

               $K_{c} = \frac{[CH_{3}OH]}{[CO][H_{2}]^{2}}$

                       = $\frac{2.4}{2.4 \times (2.4)^{2}}$

                       = 0.173

Thus, we can conclude that equilibrium constant for the given reaction is 0.173.