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Shtirlitz [24]
3 years ago
15

Calculate the value of [CH3OH][CO][H2]2 when all concentrations are 2.4. Keep in mind that the reaction may not be at equilibriu

m under these conditions.
Chemistry
1 answer:
NikAS [45]3 years ago
3 0

Explanation:

The given reaction will be as follows.

            CO + 2H_{2} \leftrightharpoons CH_{3}OH

So, equilibrium constant for this equation will be as follows.

              K_{c} = \frac{[CH_{3}OH]}{[CO][H_{2}]^{2}}

As it is given that concentration of all the species is 2.4. Therefore, calculate the value of equilibrium constant as follows.

               K_{c} = \frac{[CH_{3}OH]}{[CO][H_{2}]^{2}}

                       = \frac{2.4}{2.4 \times (2.4)^{2}}

                       = 0.173

Thus, we can conclude that equilibrium constant for the given reaction is 0.173.  

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See the sketch attached.

<h3>Explanation</h3>

The Lewis structure of a molecule describes

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Atoms are most stable when they have eight or no electrons in their valence shell (or two, in case of hydrogen.)

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H₂O contains two hydrogen atoms and one oxygen atom. It would take an extra 2 + 2  × 1 = 4 electrons for all its three atoms are stable. Atoms in an H₂O would achieve that need by sharing electrons. It would form a total of 4 / 2 = 2 O-H bonds.

Each O-H bond contains one electron from oxygen and one from hydrogen. Hydrogen has no electron left. Oxygen has six electrons. Two of them have went to the two O-H bonds. The remaining four become 4 / 2 = 2 lone pairs. The lone pairs repel the O-H bonds. By convention, they are placed on top of the two H atoms.

Similarly, atoms in a SO₂ molecule demands an extra 2 × 2 + 2 = 6 electrons for its three atoms to become chemically stable. It would form 6 / 2 = 3 chemical bonds. Loops are unlikely in molecules without carbon. As a result, one of the two O atoms would form two bonds with the S atom while the other form only one.

Atoms are unstable with an odd number of valence electrons. The S atom in SO₂ would have become unstable if it contribute one electron to each of the three bond. It would end up with 3 × 2 + 3 = 9 valence electrons. One possible solution is that it contributes two electrons in one particular bond. One of the three bonds would be a coordinate covalent bond, with both electrons in that bond from the S atom. In some textbooks this type of bonds are also known as dative bonds.

Dots and crosses denotes the origin of electrons in a bond. Use the same symbol for electrons from the same atom. Electrons from the oxygen atoms O are shown in blue in the sketch. They don't have to be colored.

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