Calculate the value of [CH3OH][CO][H2]2 when all concentrations are 2.4. Keep in mind that the reaction may not be at equilibriu
1 answer:
Explanation:
The given reaction will be as follows.
So, equilibrium constant for this equation will be as follows.
As it is given that concentration of all the species is 2.4. Therefore, calculate the value of equilibrium constant as follows.
=
= 0.173
Thus, we can conclude that equilibrium constant for the given reaction is 0.173.
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Answer:
Carbon dioxide
Explanation:
Neither helium nor carbon dioxide has a molecular dipole, so their strongest van der Waals attractive forces are London forces.
Helium is a small spherical atom with only a two electrons, so its atoms have quite weak attractions to each other.
CO₂ is a large linear molecule. It has more electrons than helium, so the attractive forces are greater. Furthermore, the molecules can align themselves compactly side-by-side and maximize the attractions (see below).
For example. CO₂ becomes a solid at -78 °C, but helium must be cooled to -272 °C to make it freeze (that's just 1 °C above absolute zero).
