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NeTakaya
1 year ago
7

The tendency of an atom to pull electrons toward itself is referred to as its _____. ionic potential tonicity covalency electron

egativity polarity
Chemistry
1 answer:
larisa86 [58]1 year ago
4 0

Electronegativity

The tendency of an atom to pull electrons towards itself is called electronegativity.

It is the tendency of an atom to attract bonding pair of electrons towards itself. These atoms which are more electronegative are able to bear a negative charge and be stable.

Unlike electropositive elements which tend to lose electrons , electronegative elements hold on tightly to the electrons.

The electronegativity is measured using the Pauling Scale where the most electronegative element of the periodic table, Fluorine , is given a value of 4 and the rest of the elements have values lower than 4 according to the trends followed by their groups and periods.

The least electronegative element of the periodic table , Cesium has a value of 0.7 on the Pauling Scale.

Electronegativity increases when we move from left to right in the periodic table and it decreases (in general) when we move down the group.

(To know more about Electronegativity: https://brainly.in/question/5742635 )

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All of them affect the DNA

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A science teacher asked students to calculate the density of a toy block. The mass of the block was 110 grams and the volume of
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The carton fe3+ is formed when
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What element is an atom that has 7 protons 8 neutrons and 6 electrons?
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Read 2 more answers
Calculate the solubility of ( = ) in moles per liter. Ignore any acid–base properties. s = mol/L Calculate the solubility of ( =
BaLLatris [955]

This is an incomplete question, here is a complete question.

Calculate the solubility of each of the following compounds in moles per liter. Ignore any acid-base properties.

CaCO₃, Ksp = 8.7 × 10⁻⁹

Answer : The solubility of CaCO₃ is, 9.33\times 10^{-5}mol/L

Explanation :

As we know that CaCO₃ dissociates to give Ca^{2+} ion and CO_3^{2-} ion.

The solubility equilibrium reaction will be:

CaCO_3\rightleftharpoons Ca^{2+}+CO_3^{2-}

The expression for solubility constant for this reaction will be,

K_{sp}=[Ca^{2+}][CO_3^{2-}]

Let solubility of CaCO₃ be, 's'

K_{sp}=(s)\times (s)

K_{sp}=s^2

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s=9.33\times 10^{-5}mol/L

Therefore, the solubility of CaCO₃ is, 9.33\times 10^{-5}mol/L

4 0
3 years ago
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