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MariettaO [177]
3 years ago
13

Determine the a) energy (in eV) and b) wavelength (in cm) corresponding to blue light of frequency 670 THz

Chemistry
1 answer:
Lesechka [4]3 years ago
7 0

Answer :

(a) The energy of blue light (in eV) is 2.77 eV

(b) The wavelength of blue light is 4\times 10^{-5}cm

Explanation:

The relation between the energy and frequency is:  

Energy=h\times Frequency

where,

h = Plank's constant = 6.626\times 10^{-34}J.s

Given :

Frequency = 670THz=670\times 10^{12}s^{-1}

Conversion used :

1THz=10^{12}Hz\\1Hz=1s^{-1}\\1THz=10^{12}s^{-1}

So,  

Energy=(6.626\times 10^{-34}J.s)\times (670\times 10^{12}s^{-1})

Energy=4.44\times 10^{-19}J

Also,  

1J=6.24\times 10^{18}eV

So,  

Energy=(4.44\times 10^{-19})\times (6.24\times 10^{18}eV)

Energy=2.77eV

The energy of blue light (in eV) is 2.77 eV

The relation between frequency and wavelength is shown below as:

Frequency=\frac{c}{Wavelength}

Where,

c = the speed of light = 3\times 10^8m/s

Frequency = 670\times 10^{12}s^{-1}

So, Wavelength is:

670\times 10^{12}s^{-1}=\frac{3\times 10^8m/s}{Wavelength}

Wavelength=\frac{3\times 10^8m/s}{670\times 10^{12}s^{-1}}=4\times 10^{-7}m=4\times 10^{-5}cm

Conversion used : 1m=100cm

The wavelength of blue light is 4\times 10^{-5}cm

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High concentrations of ammonia (NH3), nitrite ion, and nitrate ion in water can kill fish. Lethal concentrations of these specie
kykrilka [37]

Explanation:

It is known that molality is the number of moles present in kg of solution.

Mathematically,  Molality = \frac{\text{no. of moles of solute}}{\text{mass of solvent in Kg}}

The given data is as follows.

Molar mass of ammonia = 17 g/mol

Concentration = 1.002 mg/L = \frac{0.001002 g/L}{17 g/mol}

                        = 5.89 \times 10^{-4} mol/L

Also,    density = \frac{1 g}{mL} = 1 kg/L

Therefore, molality will be calculated as follows.

        Molality = \frac{5.89 \times 10^{-4} mol/L}{1 kg/L}

                      = 5.89 \times 10^{-4} mol/kg

And,

Molar mass of nitrite = 46 g/mol

Concentration = 0.387 mg/L = \frac{0.000412 g/L}{46 g/mol}

                        = 8.956 \times 10^{-6} mol/L

And, density = \frac{1 g}{mL} = 1 kg/L

Hence, molality = \frac{8.956 \times 10^{-6} mol/L}{1 kg/L}

                          = 8.956 \times 10^{-6} mol/kg  

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                              = 0.02181 mol/L

Also, density = \frac{1 g}{mL} = 1 kg/L

Hence, molality will be calculated as follows.

         Molality = \frac{0.02181 mol/L}{1 kg/L}

                       = 0.02181 mol/kg

Therefore, molality of given species is 5.89 \times 10^{-4} mol/kg  for ammonia, 8.956 \times 10^{-6} mol/kg  for nitrite, and 0.02181 mol/kg for nitrate ion.

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3 years ago
2 HI(g) ⇄ H2(g) + I2(g) Kc = 0.0156 at 400ºC 0.550 moles of HI are placed in a 2.00 L container and the system is allowed to rea
Alex_Xolod [135]

<u>Answer:</u> The concentration of hydrogen gas at equilibrium is 0.0275 M

<u>Explanation:</u>

Molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}

Moles of HI = 0.550 moles

Volume of container = 2.00 L

\text{Initial concentration of HI}=\frac{0.550}{2}=0.275M

For the given chemical equation:

                          2HI(g)\rightleftharpoons H_2(g)+I_2(g)

<u>Initial:</u>                  0.275

<u>At eqllm:</u>           0.275-2x      x         x

The expression of K_c for above equation follows:

K_c=\frac{[H_2][I_2]}{[HI]^2}

We are given:

K_c=0.0156

Putting values in above expression, we get:

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Neglecting the negative value of 'x' because concentration cannot be negative

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Answer:

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The law states that "equal volumes of all gases at the same temperature and pressure contains equal number of molecules or moles".

The law describes the behavior of gases when involve in chemical reactions. It enables one to change over at will in any statement about gases from volumes to molecules and vice versa.

So, the right option is B which implies that equal amounts of all gases have the same volume at the same conditions.

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