A 7780 ‑kg car is travelling at 30.7 m/s when the driver decides to exit the freeway by going up a ramp. After coasting 404 m al
1 answer:
You might be interested in
Answer:
1.907 x 10⁻⁵ J.
Explanation:
Given,
Volume of space, V = 5.20 m³
Assuming the intensity of sunlight(S) be equal to 1.1 x 10³ W/m².
Electromagnetic energy = ?
where c is the speed of light.
Hence, Electromagnetic energy is equal to 1.907 x 10⁻⁵ J.
Answer:
v = 29.4 m / s
Explanation:
For this exercise we can use the conservation of mechanical energy
Lowest starting point.
Em₀ = K = ½ m v²
final point. Higher
= U = m g h
Let's use trigonometry to lock her up
cos 60 = y / L
y = L cos 60
Height is the initial length minus the length at the maximum angle
h = L - L cos 60
h = L (1- cos 60)
energy is conserved
Em₀ = Em_{f}
½ m v² = mgL (1 - cos 60)
v = 2g L (1- cos 60)
let's calculate
v² = 2 9.8 3.0 (1- cos 60)
v = 29.4 m / s