How much force is applied if a 130kg mass is accelerated at 5 m/s^2?
1 answer:
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Answer:
V = 3.54 m/s
Explanation:
Using the conservation of energy:
so:
where w is te weigh of kelly, h the distance that kelly decends, m is the mass of kelly and V the velocity in the lowest position.
So, the mass of kelly is:
m = 425N/9.8 = 43.36 Kg
and h is:
h = 1m-0.36m =0.64m
then, replacing values, we get:
Solving for v:
V = 3.54 m/s