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jasenka [17]
3 years ago
6

What can Lisa do to increase the strength of the electromagnet? She can use a nail with weaker magnetic properties. She can chan

ge the direction of the nail. She can increase the number of wire loops. She can reduce the current in the wire.
Physics
2 answers:
Kryger [21]3 years ago
7 0

Answer:

C

Explanation:

Edge2021

Illusion [34]3 years ago
3 0

Answer:She can increase the number of wire loops

Explanation: When the number of loops of wire ( usually around the iron ) increases, the strength of the electromagnet is increased.

According to the equation

B=μ₀ N I

Where

μ₀ = permeability of the core

N= Number of turns of the coil

I= Current flowing through the coil

From the equation above , we can see that The strength of an electromagnet depends the amount of current, no of turns of coil and the permeability  core of coil. we can now say that Increasing the  number of wire loops  increases the strength of electromagnet.

Therefore, Lisa should increase the number of wire loops to increase the strength of the electromagnet

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PLS HELP DUE IN 30 MINS!!! True or false: A large-amplitude pulse travels at a faster speed than a small-amplitude pulse. Explai
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Answer:

False

Explanation:

Larger pulse with more energy means that the wave has large amplitude. As in the given question, both the waves are travelling in the same medium, hence their speeds will remain same and therefore the larger pulse will not overtake the smaller pulse. Remember the amplitude of a wave does not affect the speed at which the wave travels

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suppose that a block is pulled 16 meters across a floor. what amount of work is done if the force used to drag the block is 22n
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Work = (force) x (distance)

Work = (22 N) x (16 m)

<em>Work = 352 Joules</em>

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A converging lens brings rays of light together at a focal point. the bending of light rays is the result of
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Which of the following has potential but not kinetic energy?
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Answer:

<h2>D.)</h2>

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How much heat must be removed from 456 g of water at 25.0°C to change it into ice at - 10.0°C?
Svet_ta [14]

Answer:

229,098.96 J

Explanation:

mass of water (m) = 456 g = 0.456 kg

initial temperature (T) = 25 degrees

final temperature (t) = - 10 degrees

specific heat of ice = 2090 J/kg

latent heat of fusion =33.5 x 10^(4) J/kg

specific heat of water = 4186 J/kg

for the water to be converted to ice it must undergo three stages:

  • the water must cool from 25 degrees to 0 degrees, and the heat removed would be Q = m x specific heat of water x change in temp

        Q = 0.456 x 4186 x (25 - (-10)) = 66808.56 J

  • the water must freeze at 0 degrees, and the heat removed would be Q = m x specific heat of fusion x change in temp

         Q = 0.456 x 33.5 x 10^(4) = 152760 J

  • the water must cool further to -10 degrees from 0 degrees, and the heat removed would be Q = m x specific heat of ice x change in temp

        Q = 0.456 x 2090 x (0 - (-10)) = 9530.4 J

The quantity of heat removed from all three stages would be added to get the total heat removed.

Q total = 66,808.56 + 152,760 + 9,530.4 = 229,098.96 J

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3 years ago
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