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jasenka [17]
2 years ago
6

What can Lisa do to increase the strength of the electromagnet? She can use a nail with weaker magnetic properties. She can chan

ge the direction of the nail. She can increase the number of wire loops. She can reduce the current in the wire.
Physics
2 answers:
Kryger [21]2 years ago
7 0

Answer:

C

Explanation:

Edge2021

Illusion [34]2 years ago
3 0

Answer:She can increase the number of wire loops

Explanation: When the number of loops of wire ( usually around the iron ) increases, the strength of the electromagnet is increased.

According to the equation

B=μ₀ N I

Where

μ₀ = permeability of the core

N= Number of turns of the coil

I= Current flowing through the coil

From the equation above , we can see that The strength of an electromagnet depends the amount of current, no of turns of coil and the permeability  core of coil. we can now say that Increasing the  number of wire loops  increases the strength of electromagnet.

Therefore, Lisa should increase the number of wire loops to increase the strength of the electromagnet

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PolarNik [594]

Answer:

The value of radiation pressure is 2.933 \times 10^{-8} Pa

Explanation:

Given:

Intensity I = 8.8 \frac{W}{m^{2} }

Area of piece A = 2.1 \times 10^{-4} m^{2}

From the formula of radiation pressure in terms of intensity,

   P = \frac{I}{c}

Where P = radiation pressure, c = speed of light

We know value of speed of light,

 c = 3 \times 10^{8} \frac{m}{s}

Put all values in above equation,

  P = \frac{8.8}{3 \times 10^{8} }

  P = 2.933 \times 10^{-8} Pa

Therefore, the value of radiation pressure is 2.933 \times 10^{-8} Pa

8 0
3 years ago
The Great Sandini is a 60 kg circus performer who is shotfrom a cannon (actually a spring gun). You don't find many men ofhis ca
d1i1m1o1n [39]

Answer:

V=15.3 m/s

Explanation:

To solve this problem, we have to use the energy conservation theorem:

U_e+K_i+U_{gi}+W_{friction}=K_f+U_{gf}

the elastic potencial energy is given by:

U_e=\frac{1}{2}*k*x^2\\U_e=\frac{1}{2}*1100N/m*(4m)^2\\U_e=8800J

The work is defined as:

W_{friction}=F_f*d*cos(\theta)\\W_{friction}=40N*2.5m*cos(180)\\W_{friction}=-100J

this work is negative because is opposite to the movement.

The gravitational potencial energy at 2.5 m aboves is given by:

U_{gf}=m*g*h\\U_{gf}=60kg*9.8*2.5\\U_{gf}=1470J

the gravitational potential energy at the ground and the kinetic energy at the begining are 0.

8800J+0+0+-100J=\frac{1}{2}*62kg*v^2+1470J\\v=\sqrt{\frac{2(8800J-100J-1470J)}{62kg}}\\v=15.3m/s

3 0
3 years ago
Which of the following describes how the current in a circuit can be increased? Select all that apply.
Anettt [7]

Answer:

B. and D. would be my best guess.

Explanation:

The reason why is because if you lower the resistance, the voltage will be higher, and if you higher the voltage, the resistance would be lower and the voltage would higher.

5 0
3 years ago
If a 2kg ball rolls down a ramp that is 15 meters long in 25 seconds, what is the
77julia77 [94]

Answer:

1.968504 ft/s

7 0
2 years ago
Bruno the bat flies at a speed of 0.5 m/s in circle of radius 1 m. What is his acceleration?
beks73 [17]

Answer:

Acceleration is 0.25m/s^2

Explanation:

Given the following :

Speed = 0.5m/s

Radius(r) of circle = 1m

Acceleration round a circular path is given as :

a = v^2 / r

Where

a = acceleration of the body

v = speed / velocity

r = radius

Therefore,

a = v^2 / r

a = (0.5)^2 / 1

a = 0.25m/s^2

7 0
2 years ago
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