<span>No. Work is not done if you carry a book across the room
at a constant velocity?
The force applied is perpendicular to the direction of motion. (C)</span>
Answer:
1. Resistance
2. Store chmical energy and transfer it to electrical energy when a circuit is connected
3.Electric current
4. Series and parallel
5. can't see diagram
6. series
7. Parallel
8. can't not see diagram
Explanation:
Answer:
272.89g
Explanation:
Find the diagram to the question in the attachment below;.
Using the principle of moment to solve the question which states that the sum of clockwise moment is equal to the sum of anticlockwise moment.
Moment = Force * Perpendicular distance
Taking the moment of force about the pivot.
Anticlockwise moment:
The 85g mass will move in the anticlockwise
Moment of 85g mass = 85×36.6
= 3111gcm
Clockwise moment.
The mass of the metre stick M situated at the centre (50cm from each end) will move in the clockwise direction towards the pivot.
CW moment = 11.4×M = 11.4M
Equating CW moment to the ACW moment we will have;
11.4M = 3111
M = 3111/11.4
M = 272.89g
The mass of the metre stick is 272.89g
Answer:
1.26 m/s²
Explanation:
Given:
Δx = 172 m
v₀ = 17.3 m/s
v = 27.1 m/s
Find: a
v² = v₀² + 2aΔx
(27.1 m/s)² = (17.3 m/s)² + 2a (172 m)
a = 1.26 m/s²
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