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3 years ago

How far will a car travel in 30 min at 40 m/s? (kilometres)

Physics

1 answer:

kondor19780726 [428]3 years ago

6 0

Answer:

72km

Explanation:

30 mins --> 30 x 60 s = 1800 s

Distance --> Speed x Time

= 40m/s x 1800s

= 72 000 m

= 72 km (1km is 1000m)

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Which statement best defines constructive interference? O Energy reflects back toward the source of its power. O Two waves with

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Answer: two waves with identical crests and troughs meet

Explanation:

My teacher gave me the answer

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3 years ago

A boulder with a weight of 780 N is resting at the edge of a cliff that rises 123 m above the ground. What is the gravitational

-Dominant- [34]

Potential energy U = mgh

Given h = 123 m,
mg = F = 780 N

Then
U = (123)(780)
= 95940
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3 years ago

If then hypothesis for egg drop

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3 years ago

On a caterpillars map all distances are marked in kilometers . The caterpillars map shows the distance between two milkweed plan

frutty [35]

Answer:

The distance in kilometers is 4012 × $10^{-6}$ km.

Explanation:

We know that the conversion of 1 millimeters is equal to $10^{-3}$ meter. And then the conversion of 1 meter is equal to $10^{-3}$ km. Then the conversion of 1 millimeter to km will be

1 mm = $10^{-3}$ m

1 m = $10^{-3}$ km

So, 1 mm = $10^{-3}$ × $10^{-3}$ km = $10^{-6}$ km.

As here the the distance is 4012 mm, then the distance in km will be

4012 mm = 4012 × $10^{-6}$ km.

So the distance is 4012 × $10^{-6}$ km.

5 0

3 years ago

A tennis ball is thrown vertically upward with an initial velocity of +6.2 m/s. What will the ball’s velocity be when it returns

anastassius [24]

Answer:

$v_{f}=-6.2 m/s$

Explanation:

The ball will rise decreasing its speed until it reaches the highest point where its speed will be zero. From this point the tennis ball will begin to fall again, in the free fall the tennis ball will gain speed but now in the opposite direction. When it returns to the same point where it was launched, its speed will be the same as the one that was launched but with the opposite sign.

$v_{f}=-6.2 m/s$

We can check this using the equation:

$v_{f}^2=v_{i}^2+2gh$

where $v_{i}=+6.2 m/s$

ang h is the height, but because the ball returns to the same point where it started, h =0

then

$v_{f}^2=v_{i}^2$

$v_{f}=v_{i}$

the initial and final velocity will be the same in number, but we know that the ball is going in the opposite direction, so the final velocity must have the opposite sign from the initial velocity

so if $v_{i}=+6.2 m/s$ ,

$v_{f}=-6.2 m/s$

4 0

3 years ago