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LekaFEV [45]
3 years ago
10

Using the videos and websites provided, or other online resources you find, and analyze the events of the Biosphere 2 story and

history.
Biosphere 2 Research Resources

A: Arizona's Beautiful Biodome Failure
B: Biosphere 2: 25 Years Scientists Lived Inside
C: TED Talk about life in Biosphere 2
D: Biosphere 2: Not Such a Bust
E: Biosphere 2: An American Space Odyssey


In the chart below:
Decide which events, components, or aspects contributed to the success or failure of Biosphere 2. You must include a minimum of 5 events, components, aspects of the project.

Provide evidence of these successes or failures from your research.

Include the citation of the resource where you found this information.


Biosphere event, component, or aspect (ex: one Biospherian needing to leave temporarily)
Min. of 5 required
Success (S) or Failure (F)?
Evidence of success or failure from the provided resources
Citation (Letter)
Physics
2 answers:
Andru [333]3 years ago
4 0
Your answer has to be B
Likurg_2 [28]3 years ago
4 0
Get an app called SOCRATIC works like a charm
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A ray of light traveling through air strikes a piece of diamond at an angle of incidence equal to 56 degrees. Calculate the angu
Montano1993 [528]

Answer:

The angle of separation is  \Delta \theta =  0.93 ^o

Explanation:

From the question we are told that

    The angle of incidence is  \theta  _ i  = 56^o

     The refractive index of violet light  in diamond  is  n_v = 2.46

       The refractive index of red light in diamond is n_r = 2.41

      The wavelength of violet light is  \lambda _v = 400nm = 400*10^{-9}m

         The wavelength of red  light is  \lambda _r = 700nm = 700*10^{-9}m

Snell's  Law can be represented mathematically as

         \frac{sin \theta_i}{sin \theta_r} = n

Where \theta_r is the angle of refraction

=>       sin \theta_r  =   \frac{sin \theta_i}{n}

Now considering violet light

               sin \theta_r__{v}}  =   \frac{sin \theta_i}{n_v}

substituting values

                sin \theta_r__{v}}  =   \frac{sin (56)}{2.46}

                 sin \theta_r__{v}}  =  0.337

                 \theta_r__{v}}  =  sin ^{-1} (0.337)

                 \theta_r__{v}}  =  19.69^o

Now considering red light

               sin \theta_r__{R}}  =   \frac{sin \theta_i}{n_r}

substituting values

                sin \theta_r__{R}}  =   \frac{sin (56)}{2.41}

                 sin \theta_r__{R}}  =  0.344

                 \theta_r__{R}}  =  sin ^{-1} (0.344)

                 \theta_r__{R}}  = 20.12^o

The angle of separation between the red light and the violet light is mathematically evaluated as

                  \Delta \theta = \theta_r__{R}} -  \theta_r__{V}}

substituting values

                  \Delta \theta =20.12 - 19.69

                  \Delta \theta =  0.93 ^o

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