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jarptica [38.1K]
3 years ago
10

What is the volume of a cube if the length measures 2 cm?

Mathematics
1 answer:
-BARSIC- [3]3 years ago
6 0

Answer:

=L*b*h

length,berth,highte

=2*2*2

=8cm^3

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DanielleElmas [232]

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Easy math pls help quick

Step-by-step explanation:Easy math pls help quick

is your correct answer

8 0
2 years ago
HELP DUE SOON!<br><br> x = ?? degrees
rjkz [21]

Answer:

Step-by-step explanation:

Tricky. Very neat.

You are missing the minor arcAC and you need it, but don't fret. It can be found.

The formula for this is x = 1/2(Major Arc(235) - Minor Arc(see below) )

The minor arc is the supplement of x.

The minor arc is also equal to the the central angle

So the minor arc is 180 - x

x = 1/2 (235 - (180 - x) )                    Remove the inside  brackets

x = 1/2 (55  + x )                               Remove the remaining brackets

x = 1/2 *55 + 1/2x                             Subtract 1/2x from both sides

1/2 x = 27.5                                      Multiply both sides by 2

x = 55

4 0
3 years ago
The sum of the measures of angle x and y is 90. If the measures of angle x is 30 less than twice the measures of angle y what is
svp [43]
First set up your two equations:

x + y = 90

x = 2y - 30

Then substitute what x equals in the second equation into the first equation:

(2y -30) + y = 90

Now solve for y:

3y -30 = 90
3y = 120
y = 40

Then use y = 40 and substitute the value for y into one of your original equations and solve for x.  I'll choose the first one, but either one will work.

x+ 40 = 90
x = 50

So your solution is x = 50 and y = 40


8 0
3 years ago
Use the Pythagorean identity to do the following:
nlexa [21]

Answer:  2 - 2*sin³(θ) - √1 -sin²(θ)

Step-by-step explanation:  In the expression

cos(theta)*sin2(theta) − cos(theta)

sin (2θ) = 2 sin(θ)*cos(θ)     ⇒   cos(θ)*2sin(θ)cos(θ) - cos(θ)

2cos²(θ)sin(θ) - cos(θ)           if we use cos²(θ) = 1-sin²(θ)

2 [ (1 - sin²(θ))*sin(θ)] - cos(θ)

2  - 2sin²(θ)sin(θ) - cos(θ)  ⇒  2-2sin³(θ)-cos(θ)   ;  cos(θ) = √1 -sin²(θ)

2 - 2*sin³(θ) - √1 -sin²(θ)

7 0
3 years ago
What is the solution to the inequality (20+5 &gt; 1? 0 -3&gt;n&gt; - 2 02-2 On&lt; 2 or n &gt; 3​
Dmitry [639]

Answer:

ion know but bye

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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