The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:
Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
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Answer:
25
Step-by-step explanation:
Let n be the first integer.
Then the second integer will be (n + 1).
And the third will be (n + 2).
The sum is 78. Therefore:
Solve for n. Combine like terms:
So:
Therefore:
Therefore, the first integer is 25.
So our sequene is 25, 26, and 27.
The integer closest to zero will thus be 25.
Question :
<span>The bottom of the ladder must be 3 feet from a wall the latter is 12feet long how far above the ground does the Ladder touch the wall
</span>
Answer :
<span>11.6ft
</span>
I hope it helps and please press brain
(^_-) Rie
Answer:
Hope this helps
Step-by-step explanation:
a) x^2 + 3x = x(x+3)
b) 2x^2 - 8x = 2x(x - 4)
c) 6x + 9x^3 = 3x(2 + 3x^2)
d) 12x^3 - 4x^2 = 4x^2(3x - 1)
Answer:
One angle measures 150 degrees.
The second angle is 30 degrees.
Step-by-step explanation:
