Answer:
This question is incomplete as it lacks options, the options are:
Which change would be the most effective way to improve the validity of this experiment?
A) Increase the number of goldfish in each tank.
B) Increase the daily amount of food for each tank.
C) Create another group that is fed regular fish food.
D) Increase the number of tanks in each treatment group.
The answer is C
Explanation:
According to this question, an experiment is conducted by Trey to determine which fish food causes the most goldfish activity over a period of two weeks. In this experiment, the independent variable is the FISH FOOD which are; Swift Salmon food and Fast Flounder food. Other variables such as type of gold fish, amount of fish food, amount & type of water etc.
One of the ways to improve an experiment, which is lacking in this case is to have a CONTROL GROUP. Based on the fish foods used for each group, it is obvious that all groups in this experiment are experimental. Hence, creating another group that is fed regular fish food will serve as the CONTROL GROUP in order to compare with the experimental groups. This will improve the validity of the experiment.
The most effective way to prevent beach erosion is to replant mangrove trees, seaweeds and seagrass. The strategic planting of vegetation can be used to help control erosion. The roots of these plants help to anchor the sand and ensure that it is not carried off in erosion. This is why many areas plant seagrass and build marshes along coasts to prevent erosion.
Using the definition of kinetic energy, we have:
Answer:
Half life of S = 3.76secs
Explanation:
The concept of half life in radioactivity is applied. Half life is the time taken for a radioactive material to decay to half of its initial size.
For part 1 - How much signal will be degraded in 1secs = 1/3.9 = 0.2564
for part 2 - How much signal will be degraded in 1secs = 1/104 = 0.009615
Simply say = 1/3.9 + 1/104 = 0.266015
So both part 1 and part 2 took 1/0.266015 = 3.76secs is the half life of S when both pathways are active
Answer:
The gallon of milk is placed at a distance of 0.641 meters.
Explanation:
We have,
Mass of two 0.6 kg cartons of cereal is 1.2 kg
Length of the basket, l = 0.77 m
Center of the basket is 0.385 m
Mass of the half gallon of milk is 1.8 kg
Total weight in the basket is 1.2 + 1.8 = 3 kg
We need to find the position of the gallon of milk so that the center of mass (COM) of your groceries is at the center of the basket.
So,
(3 × 0.385) = (1.2 × 0) + (1.8 × x)
1.155 = 1.8 x
x = 0.641 meters
So, the gallon of milk is placed at a distance of 0.641 meters.
