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Colt1911 [192]
2 years ago
5

Tom Cruise jumped from one building to other building while filming the roof chase scene in Mission: Impossible - Fallout. He di

d not land on the roof of the other building safely and broke his ankle. If we assume the heights of the two building are the same and the distance between the buildings is 5 m, what is the minimum speed to land on the roof of the other building? Assume the jumping angle is 15 degrees and the air friction is negligible. (15 points) Vo =? O = 15° D = 5 m
Physics
1 answer:
OLga [1]2 years ago
3 0

Answer:

v_0=9.9\ m.s^{-1}

Explanation:

Given:

  • angle of launch of projectile from horizontal, \theta=15^{\circ}
  • range of projectile, R=5\ m

<u>We have formula  for the range of projectile:</u>

R=\frac{v_0^2\times sin\ 2\theta}{g}

putting the respective values

5=\frac{v_0^2\times sin\ 30^{\circ}}{9.8}

v_0=9.9\ m.s^{-1} is the velocity with which Tom should jump to land on the other roof.

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The SI unit for energy is Newton true or false
ipn [44]

Explanation:

false....it is joules

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6 0
2 years ago
A 5 kg wooden block sitson a flat straight-away12 meters fromthe bottom of an infinitely long ramp, which has an angle of 20 deg
saveliy_v [14]

Answer:

(a) 19.71801m/s Velocity just before going up the ramp.

(b) 74.56338m.

Explanation:

We will solve it in two parts, first we will calculate time that 5kg wooden block would take to just reach ramp and with this time we will calculate final velocity that the wooden block would have in this time.

Second, we will calculate the component of velocity vector along inclined plane and the time that it would take for velocity to be 0 meters/s then with this time we will calculate the distance that inclined plane would travel along inclined plane.

Following formulas will be used.

                                  x(t) = \frac{1}{2} t^2 = 12m =16.2m/s^2 t^2

                                 F =ma

                                 V(t) = V_{o} +at

                                 x(t) = x_{0} +v_{0}t+\frac{1}{2}a t^2

(a) Calculating velocity right before going up the ramp.

 Wooden block is going on a straightaway and has net for on it.

         F_{n} =F-F_{s} = F-uF_{n}  = 100N-0.4*9.8m/s^2*5kg =81N

     and this force produces acceleration of

      a = \frac{F}{m}=\frac{81}{5} =16.2m/s^2 .

With this acceleration, wooden block would reach at the foot of ramp in.

          x(t) = 12m = 16.2m/s^2*t^2

         t = 1.217s

and final velocity will be

v(t) = v_{0}+at = 0+16.2m/s^2*1.2171s = 19.7180m/s.

this velocity of wooden box just before going up the ramp.

(b) How far up the ramp will the wooden block go before stopping.

Ramp is at 20° relative to horizontal therefore velocity along the ramp that the wooden block would have will be.

                              V= V_{h}cos(20) = 18.5288m/s

and deceleration along the ramp is

                              a = \frac{F_{s} }{m}

 Where F_{s} force of friction along the inclined plane.

F_s =  uF_n = u*m*a

a = 9.8m/s^2*cos(20) = 9.2089m/s^2

is a component of g along normal of the inclined plane.

                               F_{s} = 0.25*5kg*9.2089m/s^2

                              = 11.5112N

                              a = \frac{11.5112N}{5kg} = 2.3022m/s^2

And with this deceleration time needed to get wooded block to stop is.

                     v(t) = v_o-at = 18.5288m/s-2.3022m/s^2*t = 0

                        t = \frac{18.5288m/s}{2.3022m/s^2} =8.04813s

 and in that time wooden block would travel

   x(8.04813s) = 18.52881m/s *8.04813s-\frac{1}{} 2.3022m/s^2*(8.0481)^2=74.56338m

This is how up wooden box will go before coming to stop.

3 0
3 years ago
PLEASE PLEASE PLEASE A mad scientist places massive amounts of charge on basketball sized aluminum balls. The charge on the ball
bazaltina [42]

Answer:

4.2 x 10⁷N

Explanation:

Given parameters:

Charge on ball:

             q₁  = 3C

              q₂ = 14C

Distance between balls  = 9000m

Unknown:

Force acting on the two balls

Solution:

The force experienced by the two charges is given by coulombs law. It is mathematically expressed as;

                      F  = \frac{k q_{1} q_{2} }{r^{2} }

where k  = 9 x 10⁹Nm²/C²

           q is the charges

             r is the distance

Input the variables and solve;

                 

        F  = \frac{9 x 10^{9} x 3 x 14 }{9000}  = 4.2 x 10⁷N

8 0
3 years ago
You are riding your bike at 9 km/h twn minutes later your speed is 6 km/h
gtnhenbr [62]

De-celleration because speed is lower as time goes on


5 0
3 years ago
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In an experiment the hypothesis is if the wavelength of the light shining on a plant is shortened the rae of the photosynthesis
suter [353]
The independent variable in any experiment is what YOU change
and then you look to see the result of the change.

In this experiment, the independent variable is the wavelength of
the light. (A)  Nothing happens until the person doing the experiment
changes the wavelength of the light.  When he DOES that, he looks
to see whether it affected the health and behavior of the plants.
8 0
3 years ago
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