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3 years ago

11 less than three times a number is the same as 75 less than the product of -1 and the number

Mathematics

2 answers:

Elina [12.6K]3 years ago

5 0

Inequality?

11 < 3x = 75 < -1x

bekas [8.4K]3 years ago

4 0

11 less than (-11) 3 times a number (3n) is the same as (=) 75 less than (-75) the product of -1 and the number (-1 times n or -n)

-11+3n=-75-n
solve
add n to both sides
-11+4n=-75
add 11 to both sides
4n=-64
divide both sides by 4
n=-16

the number is -16

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A survey among freshman at a certain university revealed that the number of hours spent studying before final exams was normally

patriot [66]

Answer: 0.0775

Step-by-step explanation:

Given : Mean : $\mu = 25$

Standard deviation : $\sigma =15$

Sample size : $n=36$

Since its normal distribution , then the formula to calculate the z-score is given by :-

$z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

For x= 28.2 hours

$z=\dfrac{28.2-25}{\dfrac{15}{\sqrt{36}}}=1.28$

For x= 30 hours

$z=\dfrac{30-25}{\dfrac{15}{\sqrt{36}}}=2$

The P- value = $P(1.28$

$=P(z$

Hence, the probabiliy that the average time spent stydying for the sampe was between 28.2 and 30 hours = 0.0775

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3 years ago

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ddd [48]

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3 years ago

Read 2 more answers

An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.

Greeley [361]

Answer: 1) 0.6561 2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel. : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = $P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}$

$=(1)(0.90)^4=0.6561$

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= $P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037$

∴ The probability that more than two dish owners in the sample subscribe to at least one premium movie channel is 0.0037.

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3 years ago

Which fraction below is equivalent to 10/12?

Effectus [21]

Answer:

5/6 or 10/12 are the same 0.83

Step-by-step explanation:

6/6-5/6=1/6 left 12/12-10/12=2/12 left

5 0

3 years ago

Red Bull is the most popular energy drink in sales in the United States. Red Bull GmbH (the parent company) has observed that da

oee [108]

Answer:

The probability that on a given day below 6,214,323 drinks are sold is 0.8413.

Step-by-step explanation:

The provided information are:

Population mean $(\mu)$ = 6,205,195

Population standard deviation $(\sigma)$ = 9,120.32

Consider, X be the random variable that represents the number of drinks that are sold on a given that is normally distributed with the mean = 6,205,195 and standard deviation = 9,120.32.

The probability that on a given day below 6,214,323 drinks are sold can be calculated as:

$P(X$

It must be noted that P(Z < 1.0008) = 0.8413 has been calculated using the standard normal table.

Hence, the required probability is 0.8413.

8 0

3 years ago