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Temka [501]
2 years ago
8

11 less than three times a number is the same as 75 less than the product of -1 and the number

Mathematics
2 answers:
Elina [12.6K]2 years ago
5 0
Inequality?

11 < 3x = 75 < -1x

 
bekas [8.4K]2 years ago
4 0
11 less than (-11) 3 times a number (3n) is the same as (=) 75 less than (-75) the product of -1 and the number (-1 times n or -n)

-11+3n=-75-n
solve
add n to both sides
-11+4n=-75
add 11 to both sides
4n=-64
divide both sides by 4
n=-16

the number is -16
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fiasKO [112]

Answer: tan(E)=1.70

Step-by-step explanation:

For this exercise you need to remember the following Trigonometric Identity:

tan\alpha =\frac{opposite}{adjacent}

You must observe the figure given in the exercise.

You can notice that the given triangle EFG is a Right triangle (Right triangles are defined as those triangles that have an angle that measures 90 degrees).

So, you can identify in the figure that:

\alpha=E\\\\ opposite=FG=56\\\\adjacent=EF=33

So, knowing these values, you can substitute them into  tan\alpha =\frac{opposite}{adjacent} and then you must evaluate (Remember to round the result to the nearest hundreth).

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Gemiola [76]

\huge\text{Hey there!}

\large\boxed{\mathsf{\dfrac{6x^2}{y^3}}}\\\\\large\boxed{= \mathsf{\dfrac{6(4^2)}{4^3}}}\\\\\large\boxed{= \mathsf{\dfrac{6(4\times4)}{4\times4\times4}}}\\\\\large\boxed{= \mathsf{\dfrac{96}{16\times4}}}}\\\\\large\boxed{= \mathsf{\dfrac{96}{64}}}\\\large\boxed{\approx \mathsf{\dfrac{96\div32}{64\div32}}}\\\large\boxed{\approx \mathsf{\dfrac{3}{2} \rightarrow \bf \dfrac{96}{64}}}

\huge\text{Thus, your answer is: \boxed{\mathsf{Option\ A. } \  \mathsf{\dfrac{96}{64}}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy}\\\huge\text{your day!}

~\frak{Amphitrite1040:)}

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