Ask question

Ask question

All categories

3 years ago

8

Describe how you could made a sound wave have a higher pitch.

2 answers:

Nimfa-mama [501]3 years ago

7 0

For the first question, you'd have to shorten the medium it is projected by.
Like on a guitar, when you press the string on the fret, you're shortening the length of the medium, therefore allowing a shorter frequency/higher pitch.

The second one, more applied energy into the sound wave would allow it to reverberate louder.

And lastly, heat is a form of energy transferred in various ways throughout our daily lives including radiation, convection, and conduction.

Hope this helped!

Anastaziya [24]3 years ago

5 0

<span>the quality of being hot; high temperature.</span>

You might be interested in

Based electromagnetic spectrum? on its surface temperature of 6,000 K, most photons that leave the Sun's surface lie in which re

masha68 [24]

Answer:

option C

Explanation:

given,

Temperature of the surface = 6000 K

using formula to calculate $\lambda_{max}$

$\lambda_{max} = \dfrac{0.0029\ K.m}{T}$

$\lambda_{max}$ is the maximum wavelength emission in meter.

T is the temperature in kelvin.

$\lambda_{max} = \dfrac{0.0029}{6000}$

$\lambda_{max} = \dfrac{0.0029}{6000}$

$\lambda_{max} = 4.8333 \times 10^{-7}$

$\lambda_{max} = 4833\ A^0$

the wavelength is in Visible range

The Correct answer is option C

7 0

4 years ago

A 1100 kg racing car accelerates from rest at a constant rate and covers a distance of 50 m in 5 s. what is the car's accelerati

allsm [11]

The car's acceleration, given the data from the question is 4 m/s²

<h3>Data obtained from the question</h3>

The following data were obtained from the question:

Initial velocity (u) = 13 m/s
Distance (s) = 50 m
Time (t) = 5 s
Acceleration (a) = 9.8

<h3>How to determine the acceleration of the car</h3>

The acceleration of the car can be obtained as illustrated below:

s = ut + ½at²

50 = (0 × 5) + (½ × a × 5²)

50 = 0 + (½ × a × 25)

50 = 0 + 12.5a

50 = 12.5a

Divide both sides by 12.5

a = 50 /12.5

a = 4 m/s²

Thus, the acceleration of the car is 4 m/s²

Learn more about acceleration:

brainly.com/question/491732

#SPJ1

8 0

2 years ago

Can someone please answer this ? it doesn’t make sense to me

s344n2d4d5 [400]

Answer:

me too I can't understand

6 0

3 years ago

A car traveling at 26.8m/s hits the brakes to slow down before turning into a neighborhood. Determine how fast it is going after

AURORKA [14]

Answer:

The speed of the car after the break was applied is 90.46 m/s

Explanation:

Given;

initial velocity of the car, u = 26.8 m/s

accelertation of the car, a = -8.2 m/s²

time of motion, t = 14.3 s

final velocity, v = ?

Apply the following kinematic equation;

v = u + at

v = 26.8 + (-8.2 x 14.3)

v = 26.8 - 117.26

v = -90.46 m/s

magnitude of the final velocity = 90.46 m/s

Therefore, the speed of the car after the break was applied is 90.46 m/s

6 0

3 years ago

An element's atomic number is 77. How many protons would an atom of this element have? protons

bulgar [2K]

Your answer is 55 protons.

6 0

3 years ago

Read 2 more answers