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marishachu [46]
3 years ago
15

Who has a greater weight to mass ratio, a person weighing 400 N or a person weighing 600 N? Select one:

Physics
1 answer:
avanturin [10]3 years ago
3 0
600 because the weigh more
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Masses A and B rest on very light pistons that enclose a fluid.There is no friction between the pistons and the cylinders they f
RSB [31]

Answer:

D)Not enough information

Explanation:

According to Pascal's principle, the pressure exerted on the two pistons is equal:

p_A = p_B

Pressure is given by the ratio between force F and area A, so we can write

\frac{F_A}{A_A}=\frac{F_B}{A_B}

The force exerted on each piston is just equal to the weight of the corresponding mass: F=W=mg, where m is the mass and g is the gravitational acceleration. So the equation becomes

\frac{m_A g}{A_A}=\frac{m_B g}{A_B}

Now we can rewrite the mass as the product of volume, V, times density, d:

\frac{V_A d_A g}{A_A}=\frac{V_B d_B g}{A_B}

We also know that A_B = 2.0 m^2\\A_A = 1.0 m^2

So we can further re-arrange the equation (and simplify g as well):

\frac{V_A d_A}{1}=\frac{V_B d_B}{2}

\frac{d_A}{d_B}=\frac{V_B}{2V_A}

We are also told that block B has bigger volume than block A: V_B > V_A. However, this information is not enough to allow us to say if the fraction on the right is greater than 1 or smaller than 1: therefore, we cannot conclude anything about the densities of the two objects.

3 0
3 years ago
If there is unequal sharing among electrons, which of the following
Dennis_Churaev [7]

Answer:

D. Fluorine.

Explanation:

For an atom to accept an electron, from another atom, it must have high electron affinity compared to the other elements.

Large atoms then to have high electron affinity compared to smaller atoms and most large atoms are non metals while elements with smaller atomic radius are metals. Tin(Sn), Arsenic(As) are metals and they have lower electrons affinity compared to Sulfur (S) and Fluorine (F).

Fluorine have a high electron affinity than Sulfur and hence has a larger atomic radius and can easily draw most of the electrons shared between the two atoms.

There's a trend to electron affinity and I.e it increases down the period and decreases down the group.

Most group (VII)A elements form electrovalent compounds due to their tendency to pull the shared electron towards them(high electron affinity) compared to Sulfur (a group VIA) element.

6 0
3 years ago
A sample of gas has a volume of 25L at a pressure of 200 kPa and a temperature of 25°C. What would be the volume if the pressure
frozen [14]

Answer:

18 L

Explanation:

Use ideal gas law:

PV = nRT

Find initial number of moles, but first convert to units that match the gas constant units.

(200,000 Pa) (0.025 m³) = n (8.314 Pa m³ / mol / K) (25 + 273.15 K)

n = 2.017 mol

At the new pressure and temperature:

(250,000 Pa) V = (2.017 mol) (8.314 Pa m³ / mol / K) (0 + 273.15 K)

V = 0.018 m³

V = 18 L

3 0
4 years ago
A transformer is to be used to provide power for a computer disk drive that needs 6.4 V (rms) instead of the 120 V (rms) from th
Amanda [17]

Answer:

The current in the primary is 0.026 A

Explanation:

Using the formula

I1 = (V1/V2)*I2

we have

I1 = (6.4/120)*0.500

I1 = 0.026 A

8 0
3 years ago
The rainbow of visible colors in the electromagnetic spectrum varies continuously from the longest wavelengths (the reddest colo
Bogdan [553]

Answer:

4.58\times 10^{14}Hz 5.825\times 10^{14}Hz 6.31\times 10^{14}Hz

Explanation:

We know that there is a relation between the speed of light ,frequency and wavelength.This relation can be given as v=\nu \lambda where v is speed of light \nu is frequency of light \lambda is wavelength of light

In first case we have given λ=655 nm

so using formula  v=\nu \lambda

3\times 10^8=655\times 10^{-9}\times \nu

\nu =4.58\times 10^{14} Hz

In second case we have wavelength 515 nm so by using above formula

3\times 10^8=515\times 10^{-9}\times \nu

\nu =5.825\times 10^{14}\ Hz

In third case we have wavelength 475 nm

so 3\times 10^8=475\times 10^{-9}\times \nu

\nu =6.31\times 10^{14}Hz

3 0
4 years ago
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