Answer:
Step-by-step explanation:
12.718 units
Step-by-step explanation:
The coordinates of the vertices of parallelogram WXYZ are given to be W(0,-1), X(4,0), Y(3,-2) and Z(-1,-3).
So, the perimeter of the parallelogram will be 2(WX + XY) {Since opposite sides of parallelogram are same in length}
Now, length of WX = units, To find the units click this link :
https://tex.z-dn.net/?f=%5Csqrt%7B(-1)%5E%7B2%7D%20%2B%204%5E%7B2%7D%20%7D%20%3D%20%5Csqrt%7B17%7D%20%3D%204.123
And, length of XY = units, To find the units click this link :
https://tex.z-dn.net/?f=%5Csqrt%7B(4-3)%5E%7B2%7D%20%2B%20(0-(-2))%5E%7B2%7D%7D%20%3D%20%5Csqrt%7B5%7D%20%3D%202.236
Therefore, the perimeter of the parallelogram WXYZ = 2(4.123 + 2.236) = 12.718 units. (Answer)
Answer:
(10-2)÷4.
Step-by-step explanation:
We are to select the correct expression that represents a number that is one fourth as great as 10-2.
Let the required number be represented by x.
Question 60:
The answer is B. 25.57.
Mean is calculated by adding up all the values of a data set, and then dividing that sum by the amount of values.
25, 32, 16, 21, 30, 18, 37=179
179÷7=25.57
Question 61:
The answer is A. 102.
Mode is the number in a data set that appears most often. 102 shows up twice, while the other values only appear once. So 102 is the mode.
Given a complex number in the form:
![z= \rho [\cos \theta + i \sin \theta]](https://tex.z-dn.net/?f=z%3D%20%5Crho%20%5B%5Ccos%20%5Ctheta%20%2B%20i%20%5Csin%20%5Ctheta%5D)
The nth-power of this number,
, can be calculated as follows:
- the modulus of
is equal to the nth-power of the modulus of z, while the angle of
is equal to n multiplied the angle of z, so:
![z^n = \rho^n [\cos n\theta + i \sin n\theta ]](https://tex.z-dn.net/?f=z%5En%20%3D%20%5Crho%5En%20%5B%5Ccos%20n%5Ctheta%20%2B%20i%20%5Csin%20n%5Ctheta%20%5D)
In our case, n=3, so
is equal to
![z^3 = \rho^3 [\cos 3 \theta + i \sin 3 \theta ] = (5^3) [\cos (3 \cdot 330^{\circ}) + i \sin (3 \cdot 330^{\circ}) ]](https://tex.z-dn.net/?f=z%5E3%20%3D%20%5Crho%5E3%20%5B%5Ccos%203%20%5Ctheta%20%2B%20i%20%5Csin%203%20%5Ctheta%20%5D%20%3D%20%285%5E3%29%20%5B%5Ccos%20%283%20%5Ccdot%20330%5E%7B%5Ccirc%7D%29%20%2B%20i%20%5Csin%20%283%20%5Ccdot%20330%5E%7B%5Ccirc%7D%29%20%5D)
(1)
And since
and both sine and cosine are periodic in
, (1) becomes
![z^3 = 125 [\cos 270^{\circ} + i \sin 270^{\circ} ]](https://tex.z-dn.net/?f=z%5E3%20%3D%20125%20%5B%5Ccos%20270%5E%7B%5Ccirc%7D%20%2B%20i%20%5Csin%20270%5E%7B%5Ccirc%7D%20%5D)
53y-42y=55
11y=55
Y=55/11 =5
