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Varvara68 [4.7K]
3 years ago
6

From the set {-252, -64, 64}, use substitution to determine which value of x makes the equation true.

Mathematics
1 answer:
Effectus [21]3 years ago
3 0

9514 1404 393

Answer:

  x = 64

Step-by-step explanation:

I find it easier to solve the equation, which requires 1 operation. Substituting 3 numbers requires 3 operations, so is 3 times the work. (I'm basically lazy.)

  4x = 256 . . . . given

  x = 256/4 = 64 . . . . the last of the listed values

__

Alternatively, you can let a graphing calculator or spreadsheet try the list of values for you. That result is attached.

_____

Since you know the rules of signed multiplication, you know that x must be positive. Only one answer choice is positive, so you really only need to try one number.

  4(64) = 256 . . . . true, so x = 64

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Answer:

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3 years ago
Which undefined term is used to define an angle
Gre4nikov [31]

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Read 2 more answers
in a school ,the number of boys who play cricket is 3 times as much as a number of boys who play tennis. if 12 boys, who play cr
Ierofanga [76]

Answer:

The number of boys who play tennis is 36.

Step-by-step explanation:

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number of boys who play cricket = y

x = 3 y..... (1)  

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x - 12 = y + 1 2

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8 0
3 years ago
Perform the indicated operation. Be sure the answer is reduced.
avanturin [10]
<h3>Given Equation:-</h3>

\boxed{ \rm  \frac{4x^{2}y^{3}z}{9} \times  \frac{45y}{8 {x}^{5} {z}^{5} }}

<h3>Step by step expansion:</h3>

\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times  \dfrac{45y}{8 {x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times  \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times  \dfrac{45y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times  \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times  \dfrac{5y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times  \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}z}{1} \times  \dfrac{5y}{2{x}^{3} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times  \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}}{1} \times  \dfrac{5y}{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5y \times  {y}^{3} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5y {}^{0}  \times  {y}^{3 + 1} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5 \times  {y}^{4} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \bf  \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }

\\  \\

\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}

8 0
2 years ago
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