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2 years ago

1. 2y/3 for y = 6?

Mathematics

2 answers:

Nitella [24]2 years ago

4 0

1. 4
2. 5
3. 19
Are the answers to your question

snow_lady [41]2 years ago

3 0

Answer:

★_ I hope it's helping you

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What is 2 2/3 x 3 1/3 x 2 1/3

madreJ [45]

Answer:

20 20/27

Step-by-step explanation:

(2 2/3)(3 1/3)(2 1/3) = (8/3)(10/3)(7/3) = 560/27 = 20 20/27

_____

<em>Additional comment</em>

The first two numbers can be written as a difference and a sum:

= (3 -1/3)(3 +1/3)(2 1/3)

= (3·3 -1/3·3 +3·1/3 -1/3·1/3)(2 1/3)

= (9 -1/9)(2 +1/3) = 9·2 +9·1/3 -1/9·2 -1/9·1/3 = 18 +3 -6/27 -1/27

= 20 20/27

7 0

2 years ago

*THIS IS FROM K12 MIDDLE SCHOOL*

AlexFokin [52]

Answer:

Step-by-step explanation:

the answer is 7 because -4 in the first pair and 3 from the second ordered pair is 7.The other side is 4 because 2 and -2 are 4 places away from each other

hope it helps :)

7 0

2 years ago

Read 2 more answers

The equation h(t)=−16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff. What is the init

Gwar [14]

Did you ever get this answer?? I really need it

4 0

3 years ago

Read 2 more answers

A full container of juice holds 64 fluid ounces.How many 7 fluid ounce servings of juice are in a full container?

choli [55]

There is 9 serving of 7 fluid ounces with a remainder of 1 fluid ounce

if you meant 8 fluid ounce servings then it would be 8 servings with no remainder

5 0

3 years ago

Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ

-Dominant- [34]

Answer:

$\tan(\beta)$

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something. If you have options that you're building toward, aim toward one of them.

${\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}$ and ${\sec(\theta)}={\dfrac{1}{\cos(\theta)}$

Recall the following reciprocal identity:

$\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}$

So, the original expression can be written in terms of only sines and cosines:

$\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)$

$\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }$

$\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}$

$\sin(\beta) *\dfrac{1 }{\cos(\beta) }$

$\dfrac{\sin(\beta)}{\cos(\beta) }$

Working toward one of the answers provided, this is the tangent function.

The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero. However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to $\tan(\beta)$ .

8 0

2 years ago