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Radda [10]
3 years ago
7

The slope of a line is -1/5, and the y-intercept is 5. What is the equation of the line written in general form? x - 5y - 25 = 0

x - 5y - 5 = 0 x + 5y - 25 = 0
Mathematics
2 answers:
seraphim [82]3 years ago
7 0
Answer is <span>x + 5y - 25 = 0

y - 5 = -1/5 (x-0)
y - 5 = -1/5x
-5y + 25 = x
x + 5y - 25 = 0</span>
otez555 [7]3 years ago
5 0
<h2>x + 5 y - 25 = 0</h2><h2>Option C is the correct answer.</h2>

Step-by-step explanation:

Equation of straight line is given by y = mx + c

    Slope of line , m = -1/5

    y- intercept, c = 5

Substituting

                      y=mx+c\\\\y=\frac{-1}{5}x+5\\\\y=\frac{-x+25}{5}\\\\5y=-x+25\\\\x+5y-25=0

x + 5 y - 25 = 0

Option C is the correct answer.

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<h2>Answer </h2>

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<h2>Explanation </h2>

First we are going to find the length of JN; then we are subtracting from it the length of JU plus the length of CN.

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