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Stels [109]
4 years ago
8

With similar triangles, the ratios of all three pairs of corresponding sides are equal

Mathematics
2 answers:
Elza [17]4 years ago
5 0
<h3>Yes, this is true.</h3>

To be considered similar triangles, the angles must be the exact same, and the sides must be proportional. The side lengths do not have to be exactly the same, but they must be proportional (like a ratio, suppose one triangle has a side length of 1, and the similar triangle has a side length of 3. The ratio is 1:3, and all sides will follow this ratio.)

miv72 [106K]4 years ago
3 0

Answer:

True

Step-by-step explanation:

Its on apex the answer is true

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NNADVOKAT [17]

Answer:  \frac{2x(5x + 1)}{4x - 1}

<u>Step-by-step explanation:</u>

\frac{4x^{3}-12x^{2}}{4x^{2}+7x - 2} ÷ \frac{2x^{2}-6x}{5x^{2}+11x + 2}

= \frac{4x^{2}(x - 3)}{(4x - 1)(x + 2)} ÷ \frac{2x(x - 3)}{(5x + 1)(x + 2)}

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