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arlik [135]
3 years ago
7

Solve the equation by completing the square.  ^x2- 12x = -28

Mathematics
2 answers:
vova2212 [387]3 years ago
5 0

Answer:

x = 6 + 2√2  and  x = 6 - 2√2

Step-by-step explanation:

Please write the " ^ " symbol between x and 2 here:  x^2 - 12x = -28.

Take half the coefficient of x; here that is -6.

Square this, obtaining 36.

Add 36 to, and then subtract 36 from, x^2 - 12x:  x^2 - 12x + 36 - 36.

Rewrite  x^2 - 12x + 36 as the square of a binomial:  (x - 6)^2.

Then rewrite  x^2 - 12x = -28  as (x - 6)^2 - 36 = -28.

Simplifying, (x - 6)^2 = 8.

Taking the square root of both sides, x - 6 = plus or minus 2√2.


Then the solutions are x = 6 + 2√2  and  x = 6 - 2√2

Olegator [25]3 years ago
3 0

x^2 -12 x = -28

(-12/2) ^ 2  =36

x^2 -12 x + 36 = -28 + 36

x^2 -12x + 36 = 8

(x-6)^2 = 8

take the square root of each side

x-6 = sqrt (8)    x-6 = -sqrt (8)  

you get a positive and a negative when taking                                                                 the square root

x= 6 + sqrt (8)  

x = 6 - sqrt (8)

sqrt (8) = 2 sqrt (2)

x= 6 + 2 sqrt (2)

x = 6 - 2 sqrt (2)

Answer:

x= 6 + 2 sqrt (2)

x = 6 - 2 sqrt (2)



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3 years ago
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Oduvanchick [21]

Answer:

The coordinates of the circumcenter of this triangle are (3,2)

Step-by-step explanation:

we know that

The circumcenter is the point where the perpendicular bisectors of a triangle intersect

we have the coordinates

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step 1

Find the midpoint AB

The formula to calculate the midpoint between two points is equal to

M=(\frac{x1+x2}{2},\frac{y1+y2}{2})

substitute the values

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step 2

Find the equation of the line perpendicular to the segment AB that passes through the point (-2,2)

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y=2 -----> equation A

step 3

Find the midpoint BC

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substitute the values

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step 4

Find the equation of the line perpendicular to the segment BC that passes through the point (3,-1)

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3 0
3 years ago
Which of the pairs of events below is mutually exclusive?
Nady [450]

Answer:

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Step-by-step explanation:

Given four pair of events:

1. Drawing an ace of spades and then drawing another ace of spades without replacement from a standard deck of cards

2. Drawing a 2 and drawing a 4 with replacement from a standard deck of cards

3. Drawing a heart and then drawing a spade without replacement from a standard deck of cards

4. Drawing a jack and then drawing a 7 without replacement from a standard deck of cards

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Which of the pairs is mutually exclusive?

Solution:

First of all, let us have a look at the definition of mutually exclusive events.

Mutually exclusive events do not have any case in common.

In other words, two events are known as mutually exclusive when both the events can not occur at the same time.

Now, let us have a look at the given options one by one:

1. Drawing an ace of spades and then drawing another ace of spades without replacement from a standard deck of cards.

We know that there is only one ace of spades in a standard deck.

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grin007 [14]
Answer would be a (-1, ten-thirds) :)
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3 years ago
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Studentka2010 [4]

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6 0
2 years ago
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