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mixer [17]
2 years ago
12

7) Calculate which is the best deal? Fill in the blanks below for your final answer. Round your answers to the nearest penny.

Mathematics
2 answers:
vekshin12 years ago
6 0

Answer:

option b is better because it would be 6 pounds cheaper than option a

butalik [34]2 years ago
3 0
Option b is the better deal because it is $ .45 cheaper per pound than option a
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In which career would you most likely apply<br> concepts from geometry?
sladkih [1.3K]

Answer: Construction and Engineering

8 0
3 years ago
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The volume of a sphere is 2145 cubic centimeters. What is the approximate diameter of this sphere?
eimsori [14]

Answer:

d = 2(40.11 cm) = 80.22 cm

Step-by-step explanation:

The formula for volume of a sphere is V = (4/3)πr³

and here V = (4/3)πr³ = 2145 cm³

Let's simplify this equation by multiplying both sides by (3/4); this will cause (4/3) to disappear:

(3/4)(4/3)πr³ = (3/4)2145 cm³, or

                 r³ = 1608.75 cm³

Taking the cube root of both sides, we get:

                  r = 40.11 cm

Remembering that diameter = 2 times radius, we calculate the diameter:

                  d = 2(40.11 cm) = 80.22 cm

6 0
4 years ago
Which of the following is the graph of the solution set of t – 4 ≥ 4t + 8 or 3t &gt;14 – 4t?
Stells [14]

Answer:

Option (C)

Step-by-step explanation:

There are two inequalities,

t - 4 ≥ 4t + 8 ------(1)

3t > 14 - 4t ------(2)

By simplifying inequality (1),

t - 4 ≥ 4t + 8

t ≥ 4t + 8 + 4

t ≥ 4t + 12

t - 4t ≥ 12

-3t ≥ 12

t ≤ \frac{12}{(-3)}

t ≤ -4

By solving inequality (2),

3t > 14 - 4t

3t + 4t > 14

7t > 14

t > \frac{14}{7}

t > 2

From the given graphs, Option (C) will be the answer.

4 0
3 years ago
I need help on this hw
Vinil7 [7]
Its 21 because 9+10= 21

7 0
3 years ago
At a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective pa
11Alexandr11 [23.1K]

Answer:

Probability that fewer than 2 of these parts are defective is 0.604.

Step-by-step explanation:

We are given that at a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective parts 19% of the time.

A random sample of 7 parts produced by this machine is chosen.

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 7 parts

            r = number of success = fewer than 2

           p = probability of success which in our question is % of defective

                 parts produced by one of the machine, i.e; 19%

<em>LET X = Number of parts that are defective</em>

<u>So, it means X ~ Binom(n = 7, p = 0.19)</u>

Now, probability that fewer than 2 of these parts are defective is given by = P(X < 2)

    P(X < 2) = P(X = 0) + P(X = 1)

                  =  \binom{7}{0}\times 0.19^{0} \times (1-0.19)^{7-0}+ \binom{7}{1}\times 0.19^{1} \times (1-0.19)^{7-1}

                  =  1 \times 1 \times 0.81^{7} +7 \times 01.9^{1} \times 0.81^{6}

                  =  <u>0.604</u>

<em>Therefore, the probability that fewer than 2 of these parts are defective is 0.604.</em>

8 0
3 years ago
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