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garri49 [273]
3 years ago
6

Slow cooling of magma leads to the formation of large crystals, such as halite and calcite.

Chemistry
1 answer:
mihalych1998 [28]3 years ago
4 0
False h they gg be DVD BBC do Ed C rhh h do B try egg cut of C the
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What makes landing the hot air balloon a challenge?
Mariana [72]
You have to think about the fact that hot air is constantly being blown up elevating the balloon once that air is taken away it's up to the steering and the wind after that. I know that probably doesn't help did you want to know the science part? 
7 0
4 years ago
How many moles in 843.211 grams of c6h12o6?
leonid [27]
Molar mass C6H12O6 = 12 x 6 + 1 x 12 + 16 x 6 = 180 g/mol

1 mole ------------ 180 g
( moles ) --------- 843.211 g

moles = 843.211 x 1 / 180

moles = 843.211 / 180

= 4,684 moles of C6H12O6
3 0
3 years ago
What is the uppermost, horizontal area of a page?
Nookie1986 [14]
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5 0
4 years ago
The town in the video stressed using locally made goods instead of imported goods. How could using locally made goods lower CO2
ladessa [460]

Answer:

It reduces the need to import goods

Explanation:

When you buy locally, the products you buy don't come from far away, so they don't have to cross the country (or the ocean) by boat, plane or trucks to reach the market/store where you're buying, at least not from a long distance away.

The distance a vehicle travels, the less CO2 emissions it produces.

If the good you're buying is made/produced only an hour away, that's not much pollution produced compared as if the good has to come from a distant place spending days on highways to reach you.

6 0
3 years ago
The half-cell is a chamber in the voltaic cell where one half-cell is the site of the oxidation reaction and the other half-cell
tankabanditka [31]

Explanation:

In a voltaic cell, oxidation reaction occurs at anode whereas reduction reaction occurs at the cathode.

Hence, the half-cell reaction taking place at anode and cathode will be as follows.

At anode (Oxidation) : Cr(s) \rightarrow Cr^{3+}(aq) + 3e^{-} ...... (1)

At cathode (Reduction) : Ag^{+}(aq) + 1e^{-} \rightarrow Ag(s)

So, in order to balance the half cell reactions, we multiply reduction reaction by 3. Hence, reduction reaction equation will be as follows.

              3Ag^{+}(aq) + 3e^{-} \rightarrow 3Ag(s)  ........ (2)

Therefore, overall reaction will be sum of equations as (1) + (2). Thus, net reaction equation is as follows.

      Cr(s) 3Ag^{+}(aq) \rightarrow Cr^{3+}(aq) + 3Ag(s)          

         

6 0
3 years ago
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