Answer:
energy goes into the chemical and cool downs the surrounding area.
0.4 g/ml.............................
Answer:
Explanation:
<u>First mixture</u>:
40 wt% methanol - 60 wt% water 200 kg
<u>Second mixture</u>:
70 wt% methanol - 30 wt% water 150 kg
Final mixture:
If, the compositions are constant, the only variables are the mass of each mixture used in the final one, so there can be only one independent balance.
Answer:
2.11 g hydrobromic acid (correct to 3SF)
Explanation:
Molecular formula of hydrobromic acid = C2H5BrO2
mass of C2H5BrO2 = 140.96g
Beginning with what we're given, 9.03*10^21 we then make a conversion by using Avegadro's number which is 6.02*10^23 per mole (Oct. 23 at 6:02 am is national mole day :) Then, we need to convert out of moles, 140.96g hydrombromic acid per mole.
It looks like this:
9.03*10^21 molecules • (1 mol C2H5BrO2 / 6.02*10^23 molecules) • (140g C2H5BrO2 / 1 mol) = 2.1144 g C2H5BrO2
The answer should be A.
Hope this helps :-)
