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Vika [28.1K]
3 years ago
12

Calculate capacitance of two parallel flat circular conducting plates with a space d between them and radius R>>d. How goo

d an approximation is your result?
Physics
1 answer:
galina1969 [7]3 years ago
5 0

Answer:

C=\epsilon_{o}\frac{\pi R^_{2}}{d}

This result is a very good approximation, because R>>d

Explanation:

The capacitance for two parallel flat plates, with surface S, space between them d, is:

C=\epsilon_{o}\frac{S}{d} =\epsilon_{o}\frac{\pi R^_{2}}{d}

This calculation is based on the fact that the electric field is constant between the plates. This only happens if the area of the plates is much larger than the distance between them: S>>d, i.e. R>>d. If we assume these factors, the result has a very good approximation.

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Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t
bekas [8.4K]

Answer:

0.13 m/s

Explanation:

m_1 = Mass of first car = 140000 kg

m_2 = Mass of second car = 95000 kg

u_1 = Initial Velocity of first car = 0.3 m/s

u_2 = Initial Velocity of second car = -0.12 m/s

v = Velocity of combined mass

For elastic collision

m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow v=\frac{m_1u_1 + m_2u_2}{m_1 + m_2}\\\Rightarrow  v=\frac{140000\times 0.3 + 95000\times -0.12}{140000+ 95000}\\\Rightarrow v=0.13\ m/s

Their final velocity is 0.13 m/s

6 0
3 years ago
Read 2 more answers
0. The volume of a cube is 27cm3. Find the length of edge of cube.​
Dennis_Churaev [7]

Answer:

27 cm3

Explanation:

7 0
3 years ago
Water pressurized to 3.5 x 105 Pa is flowing at 5.0 m/s in a horizontal pipe which contracts to 1/3 its former area. What are th
masha68 [24]

Answer:

the pressure after contraction is 2×10^5 Pa

the speed after contraction is 15m/s

Explanation:

We were given Pressure P to be 3.5 x 10^5 that is Flowing with speed of 5.0 m/s,

For us to calculate pressure we need to calculate the area first as;

Let initial Area = A₁

And Final area A₂

We were told that in a horizontal pipe it contracts to 1/3 its former area. Which means

A₂= A₁/3.................

V₁ is the speed

the pressure and speed of the water after the contraction can be calculated using equation of continuity below

A₂V₂ = A₁V₁

But

If we substitute given value in the expresion we have

V₂ = (3A *5)/A

V₂ = 15m/s

Therefore, the speed after contraction is 15m/s

Now we can calculate the pressure using

Bernoulli's equation

p₁ + ½ρv₁² + ρgh₁ = p₂ + ½ρv₂² + ρgh₂

But we know that the pipe is horizontal, then "h" terms cancel out then

p₁ + ½ρv₁² = p₂ + ½ρv₂²

Making P₂ subject of formula we have

p₂ = 0.5ρ( V ₁² - v₂² ) + P₁

P₂=. 0.5 × 1000 (5² -15² ) + 3*10^5

=2×10^5 Pa

Therefore, the pressure after contraction is 2×10^5 Pa

7 0
3 years ago
According to the law of conservation of mass, what is the mass of water
DENIUS [597]

Answer:

<em>according to the conservation of mass,</em>

<em>according to the conservation of mass,the mass of the water is 36.04g</em><em>r</em><em>a</em><em>m</em><em>s</em><em> </em>

Explanation:

Hope It Help you

3 0
3 years ago
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In an experiment, the 1 kg cart collides with a 3 kg cart but doesn’t stick to it. Instead, the 3 kg cart gets knock forward by
notka56 [123]

Explanation:

Given that,

Mass of the cart, m_1=1\ kg

Mass of the cart 2, m_2=3\ kg            

Final speed of cart 2, v_2=0.3\ m/s

Final speed of cart 1 is 0 as it comes to rest.

Let us assume that the initial velocity of the cart 2 is 0. So using the conservation of linear momentum as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\\m_1u_1+0=0+m_2v_2\\\\m_1u_1=m_2v_2\\\\u_1=\dfrac{m_2v_2}{m_1}\\\\u_1=\dfrac{3\times 0.3}{1}\\\\u_1=0.9\ m/s

So, the initial velocity of the 1.0-kg cart is 0.9 m/s.      

8 0
3 years ago
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