Answer:
Distance, d = 299.8 meters
Explanation:
Given that,
Speed of light,
Time,
We need to find the distance covered by the light in this time. It can be calculated as :
d = 299.8 meters
So, the distance covered by the light is 299.8 meters. Hence, this is the required solution.
Answer:
Explanation:
<u><em>Given:</em></u>
Acceleration = a = 0.75 m/s²
Time = t = ?
Final Velocity = = 72 km/hr = 20 m/s
<u><em>Required:</em></u>
Initial Velocity = = ?
<u><em>Formula:</em></u>
a =
<u><em>Solution:</em></u>
For the formula becomes:
= 20 - (0.75)(20)
= 20 - 15
= 5 m/s
<u><em>In Case: If you want it in km/hr:</em></u>
= 5 * 3.6
= 18 km/hr
Answer:
137.2 in pounds and in Newton's it's 588.399
Answer:
a) t = 1.75 s
b) x = 31.5 m
Explanation:
a) The time at which Tom should drop the net can be found using the following equation:
Where:
: is the final height = 0
y₀: is the initial height = 15 m
g: is the gravity = 9.81 m/s²
: is the initial vertical velocity of the net = 0 (it is dropped from rest)
Hence, Tom should drop the net at 1.75 s before Jerry is under the bridge.
b) We can find the distance at which is Jerry when Tom drops the net as follows:
Then, Jerry is at 31.5 meters from the bridge when Jerry drops the net.
I hope it helps you!