The net force on the block parallel to the incline is
∑ F = -mg sin(θ) = ma
where m is the mass of the block, g = 9.8 m/s² is the acceleration due to gravity, θ is the angle the incline makes with the horizontal, and a is the acceleration of the block. Solving for a gives
a = -g sin(θ)
so the block would slide down the incline with acceleration
a = - (9.8 m/s²) sin(30°) = -4.9 m/s²
First convert 90km/hr to m/s.
Initiate velocity = 0m/s (car was at rest)
Final velocity is 25m/s (90km/hr converted)
25m/s - 0m/s / 8s = 3.125 m/s^s
Therefore the answer is option A (3.13m/s^2)
Answer:
Moment of Inertia, I = 0.016 kgm²
Explanation:
Mass of the ball, m = 0.20 kg
Length of the pitcher's arm, l = 0.28
Radius of the circular arc, r = 0.28 m
Moment of Inertia is given by the formula:
I = mr²
I = 0.20 * 0.28²
I = 0.20 * 0.0784
I = 0.01568
I = 0.016 kgm²
