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Andrews [41]
3 years ago
5

A bee flew 840 \text{ cm}840 cm840, start text, space, c, m, end text and landed on a flower to collect some pollen. Then the be

e flew another 330 \text { cm}330 cm330, start text, space, c, m, end text to get back to her hive. How many meters did the bee travel? 111 meter =100=100equals, 100 centimeters
Mathematics
1 answer:
Volgvan3 years ago
3 0

Answer:

The bee traveled 11.7 meters.

Step-by-step explanation:

Solution,

The bee firstlt flew 840 cm to land.

And second distance bee traveled = 330 cm

For finding the total distance traveled by bee, we have to just add first distance and second distance.

So, Total distance traveled =  first distance + second distance

Total distance traveled = 840\ cm+330\ cm=1170\ cm

Now We all  know that,  1 meter is equal to 100 cm. So, for converting 'cm' into 'meter' , we need to divide the value of total distance traveled by 100.

∴Total distance traveled =\frac{1170}{100}=11.7\ meters

Thus the bee traveled 11.7 meters to go back to her hive.

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37th term; a1 = 2.3; d = -2.3
Sindrei [870]

<u>Answer:</u>

37th term of given arithmetic sequence a_1 = 2.3; d = -2.3 is -80.5.

<u>Solution:</u>

Given that  

Need to determine 37th term, when a_1 = 2.3, d = -2.3

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<u><em>Formula for nth term of arithmetic sequence is  </em></u>

\mathrm{a}_{\mathrm{n}}=\mathrm{a}_{1}+(\mathrm{n}-1) \mathrm{d}  --- equation 1

\text { In our case } a_{1}=2.3, d=-2.3

We need to determine 37th term so n = 37.

On substituting given values in equation (1) we get

\mathrm{a}_{37}=\mathrm{a}_{1}+(37-1) \mathrm{d}

\begin{array}{l}{\Rightarrow a_{37}=2.3+(37-1)(-2.3)} \\\\ {\Rightarrow a_{37}=2.3(1-36)=2.3 \times 35=-80.5}\end{array}

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