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3 years ago

Write an expression for the sequence of operations described below.

Mathematics

1 answer:

leonid [27]3 years ago

3 0

Answer:

(a+8)/7

Step-by-step explanation:

It says to add a to 8 and THEN divide which means you have to add first.

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Chelsea shows her work in finding the solution to 4x−5=2+3(x−3). After checking her answer in the original equation, she found t

Ainat [17]

quita los paréntesis: 4x-5=2+3(x-3) multiplica paréntesis X3, elimina el paréntesis: 4x-5=2+3x-9 calcule: 4x-5= -7+3x mueve los términos y te quedará así: 4x-3x-5=-7

agrupe los términos semejantes: x=-7+5

calcular la suma, y el resultado final sería: x= -2

Step-by-step explanation:

espero te sirva

8 0

2 years ago

Read 2 more answers

At a family reunion, a family friend bring 20 lb of ice and 30 cup. Which expression show the greatest common factor , using dis

Zepler [3.9K]

Answer:

10(2+3)

Step-by-step explanation:

We are given that

Ice=20 lb

Cup=30

We have to find the expression which shows the greatest common factor using distributive property of 20 and 30.

We know that distributive property of integers a,b and c

$a\cdot(b+c)=a\cdot b+a\cdot c$

$20=2\times 10$

$30=3\times 10$

$10(2+3)=10\times 2+10\times 3$

Hence, the highest common factor of 20 and 30=10

Expression:10(2+3)

3 0

2 years ago

31% of 62 what is it i have been suffering

natita [175]

I’m pretty sure it’s 50%

3 0

2 years ago

10 kg. Is how many IB

Kitty [74]

20 kg is about twent two (22) pounds

4 0

2 years ago

Read 2 more answers

Three machines A, B, and C produce 55%, 25% and 20% respectively. The percentages of defective output are 3.5%, 4.5% and 5.5%. I

pishuonlain [190]

We are given the following information concerning the three production machines;

$\begin{gathered} Of\text{ the total production;} \\ A=55\text{ \%}=0.55 \\ B=25\text{ \%}=0.25 \\ C=20\text{ \%}=0.20 \end{gathered}$

Also, we are given the percentage of defective output as follows;

$\begin{gathered} A=3.5\text{ \%}=0.035 \\ B=4.5\text{ \%}=0.045 \\ C=5.5\text{ \%}=0.055 \end{gathered}$

Therefore, if an item is selected randomly, the probability that the item is defective would be;

$\begin{gathered} P\lbrack defective\rbrack=(0.55\times0.035)+(0.25\times0.045)+(0.20\times0.055) \\ P\lbrack\text{defective\rbrack}=0.01925+0.01125+0.011 \\ P\lbrack\text{defective\rbrack}=0.0415 \end{gathered}$

ANSWER:

The probability that the item is defective would be 0.0415

6 0

8 months ago