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baherus [9]
3 years ago
13

How to determine a midpoint for a frequency table?

Mathematics
1 answer:
Semmy [17]3 years ago
3 0
The class midpoint is the lower class limit plus the upper class limit divided by 2 . Add the midpoints column to the original table.
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What does, x, in the equation 2x-8=4 equal
vova2212 [387]
The answer is 6 since 2*6 is 12 and 12-8 is 4
6 0
4 years ago
Read 2 more answers
Suppose in a class of 60 students 5 have no siblings, 26 have one sibling, 14 have two siblings, and 15 have three siblings. Cal
Otrada [13]

The relative frequency of students who have three siblings is 25% given that there are 60 students in a class in which 5 have no siblings, 26 have one sibling, 14 have two siblings and 15 have three siblings. This can be obtained by using the formula for relative frequency.

<h3>What is the relative frequency of students who have three siblings?</h3>

Given that,

total number of students in the class = 60

number of students who have no sibling = 5

number of students who have 1 sibling = 26

number of students who have 2 sibling = 14

number of students who have 3 sibling = 15

Formula for relative frequency = f/n, where f is the number of times the data occurred, n is the total number of frequencies.

Therefore,

relative frequency of students who have three siblings = 15/60 = 0.25

In percentage ⇒ 0.25 × 100 = 25%

Hence the relative frequency of students who have three siblings is 25% given that there are 60 students in a class in which 5 have no siblings, 26 have one sibling, 14 have two siblings and 15 have three siblings.

Learn more about relative frequency here:

brainly.com/question/16832475

#SPJ4

5 0
2 years ago
Find the equation of the straight line which is perpendicular to the straight line 3x+4y=12 such that perpendicular distance fro
Effectus [21]

Answer:

<h3>3y-4x = -6</h3>

Step-by-step explanation:

First get the slope of the given line;

Given the equation of the line 3x+4y=12

Rewrite in standard form y = mx+c where m is the slope;

3x+4y=12

4y = -3x + 12

y = -3x/4 + 12/4

y = -3x/4 + 3

Hence the slope of the given line is -3/4

Since the required line is perpendicular to this line, the slope of the required line will be M = -1/(-3/4) = 4/3

Get the equation:

Substitute M = 4/3 and the point (3,2) into the point slope equation of a line as shown;

y-y0 = m(x-x0)

y - 2 = 4/3(x-3)

Cross multiply

3(y-2) = 4(x-3)

3y - 6 = 4x - 12

3y - 4x = -12 + 6

<em>3y-4x = -6</em>

<em>Hence the required equation of the line is 3y-4x = -6</em>

6 0
3 years ago
Which is the polynomial function of lowest degree that has –5, –2, and 0 as roots?
Anuta_ua [19.1K]
D f(x)=x(x+2)(x+5) is the answer
8 0
4 years ago
Read 2 more answers
8(1+5x) + 5 = 13 + 5x
Lapatulllka [165]

8(1+5x) + 5 = 13 + 5x

multiply the bracket by 8

(8)(1)=8

(8)(5x)=40x

8+40x+5=13+5x

8+5+40x=13+5x

13+40x=13+5x

move 5x to the other side

sign changes from +5x to -5x

13+40x-5x=13+5x-5x ( combine like terms)

13+35x=13

move 13 to the right side

13-13+35x=13-13

35x=0

divide both sides by 35 to get x by itself

35x/35=0/35

Answer:

x=0

5 0
3 years ago
Read 2 more answers
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