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baherus [9]
3 years ago
13

How to determine a midpoint for a frequency table?

Mathematics
1 answer:
Semmy [17]3 years ago
3 0
The class midpoint is the lower class limit plus the upper class limit divided by 2 . Add the midpoints column to the original table.
You might be interested in
Should be easy points!
Andru [333]

Answer:

Let x represent the number from the sentence.

Step-by-step explanation:

2(x) + 2(1/x) = 20/3

2x + 2/x = 20/3

multiply both sides of the equation by 3x

6x + 6 = 20x

6x - 20x + 6 = 0

6x - 18x - 2x + 6 = 0

6x(x-3 -2(x-3) = 0

(6x-2 = 0 or x-3 = 0

6x = 2 or x = 3

x = 2/6

x = 1/3

Since x represented the number

Therefore x = 1/3 or 3

4 0
3 years ago
an architect is building a seminar hall to seat 1450 people. he wants the seating to be such that the number of rows and the num
Lady_Fox [76]
The seats must be arranged in a 38 by 39 arrangement to have the minimum amount of seats used.
You can find this by finding the square root of 1450, which is 38.0788655293.

5 0
4 years ago
The residents of a city voted on whether to raise property taxes. The ratio of yes votes to no votes was 5 to 3 . If there were
dlinn [17]

\bf \begin{array}{ccll} yes&no\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 5&3\\ y&2829 \end{array}\implies \cfrac{5}{y}=\cfrac{3}{2829}\implies \cfrac{5\cdot 2829}{3}=y\implies 4715=y \\\\\\ \stackrel{\textit{total number of votes}}{yes+no}\implies 4715+2829\implies 7544

5 0
3 years ago
If you flipped two coins simultaneously, for a total of 24 times, how many times, on average, would you expect to get a head and
Bingel [31]

When two coins are flipped simultaneously 24 times, on average 12 times we will get a head and a tail.

For given question,

When two coins are tossed simultaneously, the sample space is as follows:

S = { HH, HT, TH, TT} where H denotes Head and T denotes tail.

Using the formula of probability,

P = Number of favorable outcomes/total number of outcomes,

we get,

P(HT) = 1/4

and

P(TH) = 1/4

We know that the occurrence of two mutually exclusive events is the sum of their individual probabilities.

So, P(Head on one and Tail on other)

= P(HT) + P(TH)

= 1/4 + 1/4

= 2/4

= 1/2

= 0.5

So, when two coins flipped simultaneously, the probability of flipping 2 coins and getting a head and a tail is 0.5

In this question, we need to find the number of times getting a head and a tail when two coins are flipped simultaneously 24 times

= 0.5 × 24

= 12

Therefore, When two coins are flipped simultaneously 24 times, on average 12 times we will get a head and a tail.

Learn more about the probability here:

brainly.com/question/3679442

#SPJ4

8 0
1 year ago
joshua is hiking glacier national park he has now hiked a total of 17km and is 2km short of being 1/2 of the way done with his h
elixir [45]
If he hikes another 2 km, he will be halfway there.

17+2= (1/2)x
19=(1/2)x
38=x

Final answer: The total length of the hike is 38 km
4 0
3 years ago
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