Answer is in picture below.
Use 100 grams of the compound:
ω(Cl) = 85.5% ÷ 100%.
ω(Cl) = 0.855; mass percentage of the chlorine in the compound.
m(Cl) = 0.855 · 100 g.
m(Cl) = 85.5 g; mass of chlorine.
m(C) = 100 g - 85.5 g.
m(C) = 14.5 g; mass of carbon.
n(Cl) = m(Cl) ÷ M(Cl).
n(Cl) = 85.5 g ÷ 35.45 g/mol.
n(Cl) = 2.41 mol; amount of chlorine.
n(C) = 14.5 g ÷ 12 g/mol.
n(C) = 1.21 mol; amount of carbon.
n(Cl) : n(C) = 2.41 mol : 1.21 mol = 2 : 1.
This compound is dichlorocarbene CCl₂.
Answer:
506kg
Explanation:
From the reaction equation, we can see that 3 moles of hydrogen yielded 2 moles of ammonia.
Now we need to calculate the number of moles of hydrogen reacted. This mathematically equals the mass of hydrogen reacted divided by the molecular mass of the hydrogen molecule.
The mass of hydrogen reacted is 89.5kg. This equals 89.5 × 1000g which equals 89500g. The molecular mass of hydrogen is 2g/mole ( 1 atom of hydrogen has an atomic mass unit of 1 and 1 molecule of hydrogen has 2 atoms).
Now we mathematically calculate the number of moles of hydrogen reacted to be 89500/2 which equals 44,750 moles.
If 3 moles of hydrogen yielded 2 moles of ammonia gas, then 44, 750 moles will yield 44,750 × (2/3) which equals 29,833 moles of Ammonia gas.
Now, let's calculate the mass of Ammonia gas yielded. This mathematically equals the number of moles of ammonia gas yielded multiplied by the molar mass of ammonia gas. The molar mass of ammonia gas is (14 + 3(1)) which equals 17g/mole.
Hence, the mass yielded equals 29,833 × 17 = 506167g
This equals 506,167 ÷ 1000 = 506.167kg.
Answer:
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Explanation:
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Molar mass of Na = 23 g/mol
Molar massa of Na2O = 62 g/mol
balanced chemical equation:
4 Na +
1 O2 ------>
2 Na2O
4 . 23 g Na --------------> 2 . 62 g Na2O
x -------------------------> 42,0 g Na2O
124 x = 3864
of Na