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Sliva [168]
3 years ago
11

How many grams are in 5.5 moles of H2O

Chemistry
1 answer:
larisa86 [58]3 years ago
4 0

Answer:

99•g

Explanation:

Well, ONE mole of water has a mass of 18.01⋅g⋅mol−1. and 5.5⋅mol has a mass of approx. <u>99⋅g.</u>

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How does the law of conservation of mass apply to this reaction: C2H4+O2=H2O+Co2?
pav-90 [236]
Consider the formation of water molecule. Hydrogen combines with oxygen to form  a water molecule.

 

In this case, the total mass of the reactants = total mass of the products. Also, the number of atoms of hydrogen and oxygen in the reactants side and the products side are equal.

that's all I know

3 0
3 years ago
Read 2 more answers
Why is Cl weaker base
Helen [10]
Because cl atoms are bonded with hydrogen. hydrogen bond is very strong bond
6 0
3 years ago
A sample of ammonia gas at 75°c and 445 mm hg has a volume of 16.0 l. what volume will it occupy if the pressure rises to 1225 m
ioda
In this kind of exercises, you should  use the "ideal gas" rules: PV = nRT
P should be in Pascal: 
445mmHg = 59328Pa
1225mmHg = 163319Pa

V should be in cubic meter:
16L = 0.016 m3

R = \frac{PV}{nT} = constant
\frac{P1 V1}{n T} = \frac{P2 V2}{n T}
==> P1 * V1 = P2 * V2
V2 = \frac{P1 V1}{P2} = \frac{445 0.016}{1225}
V2 = 0.00581 m3 = 5.81 L


7 0
4 years ago
A solution contains AgNO3 and Ba(NO3)2. What substance could be added to the solution to precipitate Ag ions, but leave Ba2 ions
Vera_Pavlovna [14]

Answer:

A salt containing chloride ions or hydrochloric acid.

Explanation:

Hello,

In this case, by adding a chloride-based salt or hydrochloric acid, precipitation of silver chloride could be attained by cause of its neglectable solubility in water as shown below:

Ag^+(aq)+Cl^-(aq)\rightarrow AgCl(s)

Moreover, barium chloride is highly soluble in water, for that reason it remains in aqueous solution as specified:

Ba^{2+}(aq)+2Cl^-(aq)\rightarrow BaCl_2(aq)

BaCl_2(aq)\rightarrow Ba^{2+}(aq)+2Cl^-(aq)

Best regards.

7 0
3 years ago
which resonance form would be the most stable contributor to the intermediate arenium ion produced by electrophilic bromination
valentinak56 [21]

The question is incomplete as the options are missing, however, the correct complete question is attached.

Answer:

The correct answer is option A. ( check image)

Explanation:

The most stable contributor to the intermediate arenium ion produced by electrophilic bromination of methoxybenzene in given options is option a due to the fact that this resonating form follows the octet rule is satisfied for all atoms and additional π bond is present in between C-O that makes it more stable, while in other options there are positive charge which means they do not follows octet rule completely.

Thus, the correct answer is option A. ( check image)

6 0
3 years ago
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