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3 years ago

Which expression is equivalent to 19x − 6x + 2 and why?

Mathematics

2 answers:

Sonbull [250]3 years ago

7 0

<span>2 + 13x, because (19x − 6x) + 2 = 13x + 2 = 2 + 13x</span>

Ira Lisetskai [31]3 years ago

7 0

Answer: The correct option is

(C) $2+13x$ because $(19x-6x)+2=13x+2.$

Step-by-step explanation: We are given to select the expression that is equivalent to $19x-6x+2$ with reason.

To find the equivalent expression, we need to simplify the expression.

The simplification is as follows :

$19x-6x+2=(19-6)x+2=13x+2=2+13x.$

Thus, the equivalent expression is $2+13x$ because $(19x-6x)+2=13x+2.$

Option (C) is CORRECT.

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let (-5,-7) be a point on the terminal side of theta. find the exact values of cos theta, sec theta, and cot theta

Svet_ta [14]

a. The exact value of cosθ = -5/√74

b. The exact value of secθ = -√74/5

c. The exact value of cotθ = 5/7

<h3>How to find the trigonometric ratios</h3>

Since the terminal side of the θ is the point, (-5, -7), we need to find the length of the terminal side.

So, r = √(x² + y²) where

x = -5 and
y = -7

So, r = √(x² + y²)

r = √((-5)² + (-7)²)

r = √(25 + 49)

r = √74

<h3>The value of the trigonometric ratio cosθ</h3>

Since the trigonometric ratio cosθ = x/r

Substituting the values of x and r into the equation, we have

cosθ = x/r

cosθ = -5/√74

So, the exact value of cosθ = -5/√74

<h3>The value of the trigonometric ratio secθ</h3>

Since the trigonometric ratio, secθ = r/x

Substituting the values of x and r into the equation, we have

secθ = r/x

secθ = √74/-5

secθ = -√74/5

So, the exact value of secθ = -√74/5

<h3>The value of the trigonometric ratio cotθ</h3>

Since the trigonometric ratio cotθ = x/y

Substituting the values of x and y into the equation, we have

cotθ = x/y

cotθ = -5/-7

cotθ = 5/7

So, the exact value of cotθ = 5/7

Learn more about trigonometric ratios here:

brainly.com/question/1518222

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Parker drew a triangle with no cogruent sides and a 95° angle. Classify the triangle by the lengths of its sides and measures of

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$s=12\sqrt{4t}+10$

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$\underline{x|\ 0|\ 1\ |\ 4|\ 6\ |10|12|}\\y|10|34|58|69|86|93|$

$\text{The graph in attachment}$

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