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Otrada [13]
4 years ago
7

Are the two triangles below similar? (5 points) Triangles GHI and JKL are shown. Angle H measures 95 degrees, angle I measures 5

0 degrees, side GH measures 9, side GI measures 12, angle J measures 50 degrees, angle K measures 35 degrees, side JK measures 8, side KL measures 6.
a. Yes, because the corresponding sides are proportional
b. No, because the corresponding sides are not proportional
c. Yes, because there are two pairs of congruent corresponding angles
d. No, because there are not two pairs of congruent corresponding angles

Mathematics
2 answers:
zaharov [31]4 years ago
5 0

Let me start from the word similar

Two Shapes found in universe are said to be similar, If either they are congruent, or If they are polygons their Corresponding sides are proportional and Corresponding interior angle formed by the polygons are equal.

Now Coming to Question:

We have to check whether the two  ΔGHI  and ΔJKL are similar or not

∠H=95°, ∠I=50°,∠J=50°,∠K=35°

GH=9 ,GI=12, JK=8,KL=6

By using Angle sum property of Triangle In ΔGHI

∠G+∠H+∠I=180°

∠G=180°-50°-95°

     = 180°-145°

    = 35°

Similarly, ∠L=180° -50°-35°

 =95°

but these are not pair of Corresponding Angles.That is ∠H≠∠K, ∠G≠∠J, i.e  not congruent.

So, The two triangles,GHI and JKL are not Congruent.

Option (d) No, because there are not two pairs of congruent corresponding angles. is Correct option.


Butoxors [25]4 years ago
4 0

Answer:

I believe it is D

Step-by-step explanation:

Angles must be the same, not sides. Angel K does not match angle H.

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301.44

Step-by-step explanation:

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3 years ago
A room 9m long,6m broad and 3.6 m high has one door 1.4m by 2m and two windows,each 1.6m by 75cm find: the cost of white-washing
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Answer:

The cost of white-washing the walls from inside at the rate of 22.50 per m² is 1098

Step-by-step explanation:

Step 1: Finding the area of the room

Area of the room  = Length X breadth

Length  = 9m long

Breadth =  6m broad

Area of the room  = 9 x 6 =54 square metres

Step 2: Finding the area of the door

Area of the door = Length x breadth

Breadth =  1.4m

Length = 2m

Area of the door = 1.4 x 2  = 2.8 square metres

Step 3: Finding the area of the Window

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Converting cm to m

we have

75 cm  =0.75 m

Area of the 1 window=  1.6 x 0.75 = 1.2 square metres

Step 4: Finding the area to be painted

Area to be painted = Total area of the room - area of the door - 2(area of the window)

Area to be painted = 54 - 2.8 - 2(1.2)

Area to be painted = 54 - 2.8 - 2.4

Area to be painted  = 48.8 square metres

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Answer:

-20is the answer

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Answer:

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Step-by-step explanation:

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Answer:

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