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PSYCHO15rus [73]

3 years ago

9

A trailer mechanic pushes a 2500 kg car, home to a speed v, performing a job during the 5000 J. In this process, the car moves 2

5 m. Neglecting friction between the car and roadway:
(A) What is the final velocity v of the car? (B) What horizontal force exerted on the car?

1 answer:

gregori [183]3 years ago

6 0

Hope it's visible. All the best :-D

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A toy car is moving across a table with a velocity of 7.0 m/s and drives off the end. The table is 1.8 m tall. How long will the

KatRina [158]

Answer:

Option D - 0.2 s

Explanation:

We are given;

Initial velocity; u = 7 m/s

Height of table; h = 1.8m

Now,since we want to find the time the car spent in the air, we will simply use one of Newton's equation of motion.

Thus;

h = ut + ½gt²

Plugging in the relevant values, we have;

1.8 = 7t + ½(9.8)t²

4.9t² + 7t - 1.8 = 0

Using quadratic formula to find the roots of the equation gives us;

t = -1.65 or 0.22

We can't have negative t value, thus we will pick the positive one.

So, t = 0.22 s

This is approximately 0.2 s

7 0

4 years ago

Determine the projection (magnitude and sign), or component, of vector v1 along the direction of vector v2. Your answer could be

professor190 [17]

Answer:

- 1.07 ft

Explanation:

V1 = (-5, 7, 2)

V2 = (3, 1, 2)

Projection of v1 along v2, we use the following formula

=\frac{\overrightarrow{V1}.\overrightarrow{V2}}{V2}

So, the dot product of V1 and V2 is = - 5 (3) + 7 (1) + 2 (2) = -15 + 7 + 4 = -4

The magnitude of vector V2 is given by

= $\sqrt{3^{2}+1^{2}+2^{2}}=3.74$

So, the projection of V1 along V2 = - 4 / 3.74 = - 1.07 ft

Thus, the projection of V1 along V2 is - 1.07 ft.

so we need to find the direction of v2

7 0

4 years ago

A velocity selector has a magnetic field of magnitude 0.22 T perpendicular to an electric field of magnitude 0.51 MV/m.

ohaa [14]

Answer:

speed of a particle = 2.31 × $10^{6}$ m/s

energy of proton required = 27.77 KeV

energy of electron required = 15.171 eV

Explanation:

given data

magnetic field of magnitude = 0.22 T

electric field of magnitude = 0.51 MV/m

to find out

speed of a particle and energy must protons have to pass through undeflected and energy must electrons have to pass through undeflected

solution

we know that force due to magnetic and electric field is express as

force due to magnetic field B = qvB ..............1

and force due to electric field E = qE .....................2

so without deflection force due to magnetic field = force due to electric field

so here qvB = qE

and V = $\frac{E}{B}$ ...................3

put here value

V = $\frac{0.51*10^6}{0.22}$

speed of a particle = 2.31 × $10^{6}$ m/s

and

now energy of proton required will be here as

energy of proton required = mass of proton × $\frac{V^2}{2}$

put here value

energy of proton required = 1.67 × $10^{-27}$ × $\frac{(2.31*10^6)^2}{2}$

energy of proton required = 4.45 × $10^{-15}$ J

energy of proton required = 4.45 × $10^{-15}$ J ÷ (1.602 × $10^{-19}$

energy of proton required = 27777.777 eV

energy of proton required = 27.77 KeV

and

now we get here energy of electron required that is

energy of electron required = mass of electron × $\frac{V^2}{2}$

put here value

energy of electron required = 9.11 × $10^{-31}$ × $\frac{(2.31*10^6)^2}{2}$

energy of electron required = 24.305× $10^{-19}$ J

energy of electron required = 24.305 × $10^{-19}$ J ÷ (1.602 × $10^{-19}$

energy of electron required = 15.171 eV

5 0

4 years ago

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Identify each of the following as a conductors or insulators

algol13

Answer:

these are all insulators

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Before a cell enters mitosis, what happens to the genetic information in that cell?

trasher [3.6K]

Before a cell could undergo to the process of mitosis, the cell will have to undergo first to the stage of interphase. Where it will need to pass though three stages where it will prepare before it could undergo to cell division. The cell will most likely pass to G1, S and G2 phase for it to be checked and prepared before it passes through the mitosis.

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3 years ago