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Answer:

Explanation:
Given data
Mass m=67.0 kg
Final Speed vf=8.00 m/s
Initial Speed vi=2.00 m/s
Distance d=25.0 m
Force F=30.0 N
From work-energy theorem we know that the work done equals the change in kinetic energy
W=ΔK=Kf-Ki=1/2mvf²-1/2mvi²
And

So

and we know that the force the sprinter exerted Fsprinter the force of the headwind Fwind=30.0N
So
Answer:
The angle of recoil electron with respect to incident beam of photon is 22.90°.
Explanation:
Compton Scattering is the process of scattering of X-rays by a charge particle like electron.
The angle of the recoiling electron with respect to the incident beam is determine by the relation :
....(1)
Here ∅ is angle of recoil electron, θ is the scattered angle, h is Planck's constant,
is mass of electron, c is speed of light and f is the frequency of the x-ray photon.
We know that, f = c/λ ......(2)
Here λ is wavelength of x-ray photon.
Rearrange equation (1) with the help of equation (1) in terms of λ .

Substitute 6.6 x 10⁻³⁴ m² kg s⁻¹ for h, 9.1 x 10⁻³¹ kg for
, 3 x 10⁸ m/s for c, 0.500 x 10⁻⁹ m for λ and 134° for θ in the above equation.


= 22.90°
It decreases because it gave its momentum to the other car.
Given required solution
M=10kg W=? W=Fd
v=5.0m/s F=mg
t=2.40s =10*10=100N
S=VT
=5m/s*2.4s
=12m
so W=12*100
W=1200J